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Ahat [919]
3 years ago
12

Evaluate p+(n-1) x3 for n=7 and p=9

Mathematics
1 answer:
grigory [225]3 years ago
6 0
9 + (7 - 1) x 3
= 9 + (6) x 3
= 9 + 18
= 27
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Let u = <5, 6>, v = <-2, -6>. Find -2u + 5v.
Hunter-Best [27]
\bf \begin{cases}
u = \ \textless \ 5, 6\ \textgreater \ \qquad &-2u\to -2\ \textless \ 5,6\ \textgreater \ \\
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v = \ \textless \ -2, -6\ \textgreater \ \qquad &5v\to 5\ \textless \ -2,-6\ \textgreater \ \\
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\end{cases}

scalar multiplication, now, add them up
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What is 3.89 rounded to the nearest tenths
Ksenya-84 [330]

3.89 rounded to the nearest tenth is 3.9

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You regroup and get 3.9

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Phillip bought apples from the grocery store for $2.20 per pound. If he bought 2.5 pounds of apples on Monday and 1.2 pounds of
MrRissso [65]
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6 0
3 years ago
50 points<br> PLEASE HELP ASAP
OLga [1]

Answer:

1

Step-by-step explanation:

4 0
3 years ago
a plane is flying horizontally at an altitude of 21000 feet with a ground speed of 875 feet per second. the plane passes directl
Marta_Voda [28]

Answer:

the angle is changing at a rate of 0.0375 rad/s when the time is t=8 seconds

Step-by-step explanation:

since the line D that starts from the spectator and follows the plane has the following equation

D² = x² + H² ,  where H= altitude of the plane , x= horizontal distance

then for x=v*t , where v=speed of the plane and t=time since the plane has passed overhead , we have for the elevation angle

tan θ = x/y =  v*t /H

θ = tan⁻¹ ( v*t /H)

the rate of change in the angle of the spectator's sight θ with the time is

dθ/dt = 1/1+(v*t /H)² * (v/H) = (v/H)/[1+ (v/H)²*t²]

for t=8 seconds

dθ/dt = (875 ft/s/21000 ft)/[1+ (875 ft/s/21000 ft)²*(8 s)²] = 0.0375 rad/s

therefore the angle is changing at a rate of 0.0375 rad/s when the time is t=8 seconds

6 0
4 years ago
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