Answer:
0.04746
Step-by-step explanation:
To answer this one needs to find the area under the standard normal curve to the left of 5 minutes when the mean is 4 minutes and the std. dev. is 0.6 minutes. Either use a table of z-scores or a calculator with probability distribution functions.
In this case I will use my old Texas Instruments TI-83 calculator. I select the normalcdf( function and type in the following arguments: :
normalcdf(-100, 5, 4, 0.6). The result is 0.952. This is the area under the curve to the left of x = 5. But we are interested in finding the probability that a conversation lasts longer than 5 minutes. To find this, subtract 0.952 from 1.000: 0.048. This is the area under the curve to the RIGHT of x = 5.
This 0.048 is closest to the first answer choice: 0.04746.
I believe it's 8.25 x 10-6
Answer:
Length = 17 feet, Width = 5 feet
Step-by-step explanation:
Given:
The area of a rectangular wall of a barn is 85 square feet.
Its length is 12 feet longer than the width.
Question asked:
Find the length and width of the wall of the barn.
Solution:
Let width of a rectangular wall of a barn = 
<u>As length is 12 feet longer than the width.</u>
Length of a rectangular wall of a barn = 
As we know:
Subtracting both sides by 85
As width can never be in negative, hence width of a rectangular wall of a barn = = 5 feet
Length of a rectangular wall of a barn = 
Therefore, length and width of the wall of the barn is 17 feet and 5 feet respectively.
Answer:
504
Step-by-step explanation:
In the attached file
Hope it helps
$360.00*.28= 100.80
<span>Or do a portion </span>
<span>28%/100%=100.8/x </span>
<span>Then cross multiply </span>
<span>10080=28x </span>
<span>x=360</span>
