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Archy [21]
2 years ago
9

This table shows how many male and female students attended two different

Mathematics
1 answer:
dolphi86 [110]2 years ago
5 0

The answere is 0.22

Hole dis helps u and it right

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Im just giving out points whats 2+1
omeli [17]

Answer:

3

Step-by-step explanation:

3 mah fwend omg so hard my brain hurts

4 0
3 years ago
Read 2 more answers
Need help asap please
cupoosta [38]

Answer:

c = 5

Step-by-step explanation:

IT'S THE THREE FOUR FIVE TRIANGLE!!

3^2 + 4^2 = c^2

√25 = c

c = 5

4 0
3 years ago
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Given that 2x-y÷2y-x=6÷1 find x:y​
Korolek [52]

Answer:

Example Problem

Solve 2x+3=15.

Example Answer

x=6

How to Check Your Answer with Algebra Calculator

First go to the Algebra Calculator main page.

Type the following:

First type the equation 2x+3=15.

Then type the @ symbol.

Then type x=6.

Try it now: 2x+3=15 @ x=6

Step-by-step explanation:

7 0
3 years ago
A sign standing 6 feet tall is situated 18 feet away from a flag pole. at a certain time of day the sign's shadow is 3 feet long
alexdok [17]
Observe attached picture.

On picture we have:
A = height of flagpole = x ft
B = length of flagpole's shadow = 24 ft
C = height of sign = 6 ft
D = length of sign's shadow = 3 ft

When we draw a picture representing this problem we can also add another line marked in red. This way we can see that we have two right-angle triangles. We can see that both have same angle marked with α.

We can apply trigonometry rules to find height of flagpole.

From small triangle containing sign we can find tangens function:
tan \alpha = \frac{C}{D}
Similarly we can do for large triangle containing flagpole:
tan \alpha = \frac{A}{B}

We see that these two equations have same left sides. This means that their right sides must also be same:
\frac{C}{D} = \frac{A}{B}
We can solve for A:
CB=AD \\ A= \frac{CB}{D}  \\ A= \frac{6*24}{3}  \\ A=48 ft

Height of flagpole is 48 feet.

8 0
3 years ago
In attempting to calculate the carrying capacity of a cylindrical pipe, Avery measured the outer diameter to be 2 inches, neglec
andreev551 [17]
Volume of the pipe = πr^2l
Wrong measure = π x (2)^2 x l = 4πl
Correct measure = π x (2 - 2(1/8))^2 x l = 49/16πl
error = 4πl - 49/16πl = 15/16πl

% error = ((15/16πl) / 49/16πl) x 100% = 30.6%
4 0
3 years ago
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