Answer:
The answer to your question is:
x + 2y - 4 ≥ 0 and 2x -y -3 > 0
Step-by-step explanation:
First look for two points of each line to fine the line equations
1 st line points: (2, 1) ; (0, 2)
2nd line points: (2, 1) ; (3, 3)
1st line slope
m = (2 - 1) / (0 - 2) = 1 / -2 = -1/2
2nd line slope
m = (3 - 1) / ( 3 - 2) = 2 / 1 = 2
1st line
y - 1 = -1/2 (x - 2)
2y - 2 = -1(x - 2)
2y - 2 = -x + 2
x + 2y - 4 = 0 Inequality x + 2y - 4 ≥ 0
2nd line
y - 1 = 2(x - 2)
y - 1 = 2x - 4
2x -y -3 = 0 Inequality 2x -y -3 > 0
Hello!
Because we have been asked to write the equation of a line, we will need to give the answer in slope-intercept form. Slope-intercept form uses the following formula:
y = mx + b
In the above formula, M represents the slope while B represents the y-intercept. We are asked to write the equation of a horizontal line that passes through the given point. Horizontal lines have a slope of zero (0), so we’ll begin by inserting this value into the slope-intercept formula:
y = (0)x + b
Now simplify the right side of the equation:
y = b
Now we must find the y-intercept of the line in question. We are given that it passes through point (0,3). We know that any point taking the form (0,y) lies on the y-axis and, consequently, can be classified as a y-intercept. Therefore, the y-intercept of the given line must be 3. Insert this value into the simplified equation above:
y = b
y = (3)
We have now proven that the equation of the given line is (y = 3).
I hope this helps!
Answer:
No entiendo nada de tu pregunta
It would be 3 :) hope this helps
82%18.8 it should be over 100% because the value of 82 is larger than 18.8
