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il63 [147K]
3 years ago
7

D = rt ; Solve for t

Mathematics
2 answers:
Nastasia [14]3 years ago
8 0

Answer:

T stands for time

Step-by-step explanation:

Serjik [45]3 years ago
4 0

Answer:

t = \frac{d}{r}

Step-by-step explanation:

d = rt\\\frac{d}{r} = \frac{rt}{r} \\\frac{d}{r} = t\\

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30 units^2

Step-by-step explanation:

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Could someone help me please!?!
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You can use the Pythagorean Theorem to find the length of the third side AB (Identified as "x" in the figure attached in the problem), which says that in a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the legs:

 a² = b²+c²

 As we can see the figure, the triangle does not have an angle of 90°, but it can be divided into two equal parts, leaving two triangles with a right angle. We already have the values of the hypotenuse and a leg in triangle "A" , so we can find the value of the other leg:

 b = √(a²-c²) b = √(10²-4²)
 b = 9.16

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 x = √b²+c²
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8 0
4 years ago
Katie divided a drink with a volume of 3/1/2 cups into 1/2 cup servings. How many servings did she have
Rudik [331]

7, because 3.5/0.5=7

7 0
3 years ago
A swing forward 50 degree and back 95 degree. How many degree forward must the swing go to return in starting position
-Dominant- [34]

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4 0
3 years ago
A jug has 1 litre of 10% strength cordial. How much pure cordial needs to be added to make the strength 20%?
garik1379 [7]

Answer:

The volume or amount of pure cordial to be added to the solution to make the strength 20% is 125 ml

Step-by-step explanation:

The given parameters, are;

The volume of cordial in the jug = 1 litre

The percentage strength of the cordial = 10%

The proportion of the cordial that contains pure cordial = 0.1

Therefore, the volume of pure cordial in the jug = 0.1 × 1 = 0.1 × 1000 ml = 100 ml

The volume of the solvent = The volume of the solution -  The initial volume of pure cordial

∴ The volume of the solvent = 1000 ml - 100 ml = 900 ml

To increase the concentration of the cordial to 20% is given by the relation;

x/(x+900) = 0.2

Where;

x = The total volume of the pure cordial to be added to the pure solvent

Solving, gives;

x = 0.2×(x+900) = 0.2·x + 180

x -0.2·x = 180

0.8·x = 180

x = 180/0.8 = 225 ml

The total volume of the pure cordial to be added to the pure solvent = x = 225 ml

Therefore, the volume of pure cordial to be added to the initial volume of pure cordial in the solution, which is 100 ml, is therefore given as follows;

The volume or amount of pure cordial to be added = 225 ml - 100 ml = 125 ml.

The volume or amount of pure cordial to be added = 125 ml

8 0
3 years ago
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