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3 years ago

D = rt ; Solve for t

Mathematics

2 answers:

Nastasia [14]3 years ago

8 0

Answer:

T stands for time

Step-by-step explanation:

Serjik [45]3 years ago

4 0

Answer:

$t = \frac{d}{r}$

Step-by-step explanation:

$d = rt\\\frac{d}{r} = \frac{rt}{r} \\\frac{d}{r} = t\\$

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Consider the probability distribution of a random variable x. is the expected value of the distribution necessarily one of the p

Misha Larkins [42]

The expected value of a distribution is considered as a mean, or average, for a probability distribution. It represents the center of the possible values of a variable. That doesn't necessarily mean it would be one of the possible values of x.

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4 years ago

What is the mean of the data set? 17, 24, 26, 13 4 13 20 80 plz hurry

yaroslaw [1]

Answer: 24.625

Order the numbers

Before: 17,24,26,13,4,13,20,80

After: 4,13,13,17,20,24,26,80

Add

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3 years ago

Read 2 more answers

25x = 125x + 3 x = −10 x = −9 x = −3 x = 3

ICE Princess25 [194]

Answer:

x=-9

Step-by-step explanation:

first you make the coefficients equal to each other by doing a common factor which in this case is 5. Then you have to do the variable for each time the common number is repeated which is 5^x * 5^x= 5^(x+3)*5^(x+3)*5^(x+3) This would make it equal to 5^2x=5^(3x+9). Since the non exponents are common factors you can get rid of them and solve for the exponent by doing 2x=3x+9. You solve that equation to get x=-9.

8 0

3 years ago

Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5

givi [52]

<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

$A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]$ $X=\left[\begin{array}{c}x\\y\end{array}\right]$

and $B= \left[\begin{array}{c}11\\5\end{array}\right]$

∴AX=B

$adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]$

$A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6$

∴ $A^{-1} =\frac{adj A}{|A|}$

So, $A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}$

$A^{-1} ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}$

$X =A^{-1}\times B$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c} {{\frac{1}{6} }}&{\frac{5}{6}}\ \\ {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]$

⇒ $\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c} {6}\\ {11} \end{array}\right]}$

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

7 0

3 years ago

The profit y (in dollars) for a business from selling x coats is represented by y=56x . Graph the equation.

Agata [3.3K]

Answer:

The graph of the equation is also attached.

From the graph, it is clear that at x = 0, the value of y = 0

Hence, the line passes through the origin with the y-intercept 0.

Step-by-step explanation:

The slope-intercept form of the line equation

$y = mx+b$

where

m is the slope

b is the y-intercept

Given that the profit y (in dollars) for a business from selling x coats is represented by the equation

$y=56x$

comparing with the slope-intercept form of the line equation

m = 56

Determining the y-intercept

We know that the value of the y-intercept can be determined by setting x = 0 and determining the corresponding value of y.

substitute x = 0 in the equation

y = 56(0)

y = 0

Thus, the y-intercept b = 1

Thus,

The equation y = 5x has:

The slope m = 56

The y-intercept b = 1

The graph of the equation is also attached.

From the graph, it is clear that at x = 0, the value of y = 0

Hence, the line passes through the origin with the y-intercept 0.

4 0

3 years ago