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gregori [183]
3 years ago
15

What's the ASCII code for boy ?

Computers and Technology
1 answer:
Svet_ta [14]3 years ago
7 0
Bbbhjhbvvvvvvvvvvvjfvfvgvgvgvvgvttbbtvttbtvgttvgyvthyhyyhyyttbtbtbbtbtbtbtbtbyyh
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write a program in C# that reads a set of integers and then finds and prints the sum of the even and odd integers?​
trapecia [35]

Answer:

The program in C# is as follows:

using System;

class Prog {

 static void Main() {

   int n;

   Console.WriteLine("Number of integers: ");

   n = Convert.ToInt32(Console.ReadLine());

   int evensum = 0, oddsum = 0; int inpt;

   for(int i = 0;i<n;i++){

       inpt = Convert.ToInt32(Console.ReadLine());

       if(inpt%2==0){            evensum+=inpt;        }

       else{            oddsum+=inpt;        }

   }

    Console.WriteLine(evensum);

    Console.WriteLine(oddsum);

 }

}

Explanation:

This declares n, the number of integer inputs

   int n;

This prompts for n

   Console.WriteLine("Number of integers: ");

This gets input for n

   n = Convert.ToInt32(Console.ReadLine());

This declares and initializes the even and odd sum.

   int evensum = 0, oddsum = 0; int inpt;

This iterates through n

   for(int i = 0;i<n;i++){

This gets each input

       inpt = Convert.ToInt32(Console.ReadLine());

Check for even numbers and add,if even

<em>        if(inpt%2==0){            evensum+=inpt;        }</em>

Otherwise, add input as odd

<em>        else{            oddsum+=inpt;        }</em>

   }

Print even sum

    Console.WriteLine(evensum);

Print odd sum

    Console.WriteLine(oddsum);

 }

5 0
2 years ago
The next generation ip version and successor to ipv4 is called what? ipv5 ipv6 iana ssl
Olenka [21]
I study IT,it was Ipv 6 in our textbook
4 0
3 years ago
Write a program that asks the user to enter a number of seconds. There are 60 seconds in a minute. If the number of seconds ente
frez [133]

Answer:

// here is code in c.

#include <stdio.h>

// main function

int main()

{

// variable to store seconds

long long int second;

printf("enter seconds:");

// read the seconds

scanf("%lld",&second);

// if seconds is in between 60 and 3600

if(second>=60&& second<3600)

{

// find the minutes

int min=second/60;

printf("there are %d minutes in %lld seconds.",min,second);

}

// if seconds is in between 3600 and 86400

else if(second>=3600&&second<86400)

{

// find the hours

int hours=second/3600;

printf("there are %d minutes in %lld seconds.",hours,second);

}

// if seconds is greater than 86400

else if(second>86400)

{

// find the days

int days=second/86400;

printf("there are %d minutes in %lld seconds.",days,second);

}

return 0;

}

Explanation:

Read the seconds from user.If the seconds is in between 60 and 3600 then find the minutes by dividing seconds with 60 and print it.If seconds if in between 3600 and 86400 then find the hours by dividing second with 3600 and print it. If the seconds is greater than 86400 then find the days by dividing it with 86400 and print it.

Output:

enter seconds:89

there are 1 minutes in 89 seconds.

enter seconds:890000

there are 10 days in 890000 seconds.

8 0
2 years ago
2 examples of miniature storage media ?
jeka94

Answer: Flash memory cards, USB drives and tiny hard disks.

Explanation:

6 0
3 years ago
Read 2 more answers
6.8 Code Practice<br> please can have some help please
babymother [125]
Sure what is the question though
7 0
3 years ago
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