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Finger [1]
3 years ago
15

Find the maximum and minimum values of the objective function f(x, y) and for what values of x and y they occur, subject to the

given constraints.
f(x, y) = 2x + 6y
x ≥ 0
y ≥ 0
2x + 7y ≤ 70
8x + 4y ≤ 136
Mathematics
1 answer:
Lady_Fox [76]3 years ago
5 0

Given that <em>f(x, y)</em> is a linear function, and the constraints themselves are also linear, it follows that the vertices of the feasible region are the sites of extrema of <em>f(x, y)</em>. So just find where each boundary line intersects with another line, and check the value of <em>f(x, y)</em> at each intersection.

We have

• <em>x</em> = 0 and <em>y</em> = 0   ===>   (0, 0)

• <em>x</em> = 0 and 2<em>x</em> + 7<em>y</em> = 70   ===>   <em>y</em> = 10   ===>   (0, 10)

• <em>y</em> = 0 and 8<em>x</em> + 4<em>y</em> = 136   ===>   <em>x</em> = 17   ===>   (17, 0)

• 2<em>x</em> + 7<em>y</em> = 70 and 8<em>x</em> + 4<em>y</em> = 136   ===>   (14, 6)

At these points, we respectively get

• <em>f</em> (0, 0) = 0

• <em>f</em> (0, 10) = 60

• <em>f</em> (17, 0) = 34

• <em>f</em> (14, 6) = 64

Then max <em>f(x)</em> = 64 at (14, 6) and min <em>f(x)</em> = 0 at (0, 0).

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A 13-ft ladder is leaning against a house. The distance from the bottom of the ladder to the house is 7-ft less than the distanc
Olin [163]

Answer:

12 feet

Step-by-step explanation:

As a  ladder is leaning against a house, it forms right angle triangle. And for right angleΔ, we use Pythagoras theorem.i.e

P²+B²= H²

Where,

'P' is perpendicular i.e the distance  from the top of the ladder to the ground

'B' is base i.e be the distance from the bottom of the ladder to the house

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considering 'x' as perpendicular

So, base would be 'x-7'

Applying Pythagoras theorem,

x² + (x-7)²= 13²

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OR: x-12=0 => x=12

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