Ask question

Ask question

All categories

2 years ago

10

I need this really fast can someone help me outMalik jogged 2 miles in 20 minutes. What was his rate in miles per hour?

2 answers:

Lorico [155]2 years ago

8 0

6 miles per hour that’s what I think ;)

Blababa [14]2 years ago

7 0

It would be 6 miles per hour.

mph is a unit for speed. And the formula for speed is s=distance /time

So the distance is 2 miles
And the time is 20 minutes

*for this question you need to convert the minutes to hours to get the right units

20mins =0.3 hours (approx) [20/60 to get it in hours]

2 miles/0.3 hours ≈ 6 mph

You might be interested in

F(x)=-3/5x+k and if f(30)=-11 what is the value of k

Kruka [31]

Answer:

k=20.

Explanation: First we find where f(x) has its local extrema: f'(x)=3x2−10x+3. The critical points are roots of the equation: 3x2−10x+3=0.

6 0

3 years ago

Stacy is making 2, 1/4 batches of cookies. If each batch calls for 1/3 of a cup of sugar, how much sugar will Stacy use?

Luba_88 [7]

Really hope you can read cursive and I really hope this helps! (:

4 0

3 years ago

Read 2 more answers

Rzqust [24]

Answer:

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

What percentage of 40 is 12?

dimulka [17.4K]

Answer:

12 is 3 percent of 40.

Step-by-step explanation:

If you divide 12 by 40, you get 0.3. 0.3 as a fraction is 3/100. So, it would be 3% of 100.

6 0

3 years ago

In order to estimate the difference between the average hourly wages of employees of two branches of a department store, the fol

Julli [10]

Answer:

$0.071,1.928$

Step-by-step explanation:

Downtown Store North Mall Store

Sample size n 25 20

Sample mean $\bar{x}$ $9 $8

Sample standard deviation s $2 $1

$n_1=25\\n_2=20$

$\bar{x_1}=9\\ \bar{x_2}=8$

$s_1=2\\s_2=1$

$x_1-x_2=9-8=1$

Standard error of difference of means = $\sqrt{\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}}$

Standard error of difference of means = $\sqrt{\frac{2^2}{25}+\frac{1^2}{20}}$

Standard error of difference of means = $0.458$

Degree of freedom = $\frac{\sqrt{(\frac{s_1^2}{n_1}+\frac{s_2^2}{n_2}})^2}{\frac{(\frac{s_1^2}{n_1})^2}{n_1-1}+\frac{(\frac{s_2^2}{n_2})^2}{n_2-1}}$

Degree of freedom = $\frac{\sqrt{(\frac{2^2}{25}+\frac{1^2}{20}})^2}{\frac{(\frac{2^2}{25})^2}{25-1}+\frac{(\frac{1^2}{20})^2}{20-1}}$

Degree of freedom =36

So, z value at 95% confidence interval and 36 degree of freedom = 2.0280

Confidence interval = $(x_1-x_2)-z \times SE(x_1-x_2),(x_1-x_2)+z \times SE(x_1-x_2)$

Confidence interval = $1-(2.0280)\times 0.458,1+(2.0280)\times 0.458$

Confidence interval = $0.071,1.928$

Hence Option A is true

Confidence interval is $0.071,1.928$

4 0

3 years ago