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Volgvan
3 years ago
7

When you have two shapes to compare on a coordinate plane, you can determine the scale factor, knowing that the transformation w

as a dilation. Generate instructions you would give another student to determine the scale factor.
Mathematics
2 answers:
musickatia [10]3 years ago
8 0
Assume that the initial coordinates are (x,y) and that the dilated coordinates are (x',y').

The dilation is therefore:
(x,y) ............> (x',y')

Now, let's assume that the dilation factor is k.
Therefore:
x' = kx
y' = ky

Based on the above, all the student has to do is get the initial coordinates and the final ones and then substitute in any of the above two equations to get the value of k.

Example:
Assume an original point at (2,4) is dilated to coordinates (4,8). Find the dilation factor.
Assume the dilation coefficient is k.
(x,y) are (2,4) and (x',y') are (4,8)
Therefore:
x' = kx .........> 4 = k*2 ..........> k = 2
or:
y' = ky ..........> 8 = k*4 .........> k = 2
Based on the above, the dilation coefficient would be 2.

Hope this helps :)
jarptica [38.1K]3 years ago
6 0

Sample Response: Locate two corresponding ordered pairs of the two shapes. Calculate how much the pre-image values were multiplied by to obtain the image values. This is your scale factor. You can calculate this by dividing the coordinates of the mage by the corresponding coordinates of the pre-image.

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For the following telescoping series, find a formula for the nth term of the sequence of partial sums
gtnhenbr [62]

I'm guessing the sum is supposed to be

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1=a(5k+4)+b(5k-1)

If k=-\frac45, then

1=b(-4-1)\implies b=-\frac15

If k=\frac15, then

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This means

\dfrac{10}{(5k-1)(5k+4)}=\dfrac2{5k-1}-\dfrac2{5k+4}

Consider the nth partial sum of the series:

S_n=2\left(\dfrac14-\dfrac19\right)+2\left(\dfrac19-\dfrac1{14}\right)+2\left(\dfrac1{14}-\dfrac1{19}\right)+\cdots+2\left(\dfrac1{5n-1}-\dfrac1{5n+4}\right)

The sum telescopes so that

S_n=\dfrac2{14}-\dfrac2{5n+4}

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\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}=\lim_{n\to\infty}S_n=\frac17

7 0
3 years ago
Graph this parametric equation<br><br> x = 2t y = t + 5, -2 ≤ t ≤ 3
UNO [17]
We are given the following data: <span>x = 2t, y = t + 5, -2 ≤ t ≤ 3. The data is valid since there are three unknowns in this problem and that three equations would suffice to answer the problem. 

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at t = -2 ; y = -2 + 5 = 3
at t = 3, y = 3+5 = 8

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we group the points based on their original corresponding t's 

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3 years ago
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NNADVOKAT [17]
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Find the equation of the line passing through the points (5,21) and (-5,-29)
Assoli18 [71]

Answer:

Look below

Step-by-step explanation:

lets have -29 be y2 and -5 be x2

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puteri [66]

Answer:

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Step-by-step explanation:

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3 years ago
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