Answer:
ye has bad. he nf nv nnfcnxb xx. b DC x b x dnf znfbe xngrh cngbf
Answer:
Least positive integer divisible by the numbers 2, 4, and 7 is 28
Step-by-step explanation:
We can find the least positive integer divisible by the numbers 2, 4, and 7 by taking the LCM
First lets List all prime factors for each number.
Prime Factorization of 2
2 is prime => 
Prime Factorization of 4 is:
2 x 2 => 
Prime Factorization of 7 is:
7 is prime => 
For each prime factor, find where it occurs most often as a factor and write it that many times in a new list.
The new superset list is
2, 2, 7
Multiply these factors together to find the LCM.
LCM = 2 x 2 x 7 = 28
If you would like to solve 2 * (7 - x) = 3 * (x + 3), you can do this using the following steps:
2 * (7 - x) = 3 * (x + 3<span>)
</span>2 * 7 - 2 * x = 3 * x + 3 * 3
14 - 2 * x = 3 * x + 9
14 - 9 = 3 * x + 2 * x
5 = 5 * x
x = 1
The correct result would be x = 1.
She bought 3 pots of paint so
3×5
4 brushes so
4×3
and 3 pastel crayons so
3×13
Then add them all together to get your answer
It doesn't ask you to solve just describe how you'd solve
So your answer is C