The standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2
<h3>How to represent the
quadratic function in standard form?</h3>
The quadratic function is given as
f(x) = -3x^2 + 6x - 2
The standard form of a quadratic function is represented as:
f(x) = ax^2 + bx + c
When both equations are compared, we can see that the function f(x) = -3x^2 + 6x - 2 is already in standard form
Where
a = -3
b = 6
c = -2
Hence, the standard form of the quadratic function f(x) = -3x^2 + 6x - 2 is f(x) = -3x^2 + 6x - 2
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Answer:
we need the data to answer the question
B 0.05 since the thousandth digit is higher than 5, it needs to be rounded up.
Answer:
The possible rational roots are
Step-by-step explanation:
We have been given the equation 3x^3+9x-6=0 and we have to list all possible rational roots by rational root theorem.
The factors of constant term are 
The factors of leading coefficient are 
From ration root theorem, the possible roots are the ratio of the factors of the constant term and the factors of the leading coefficient. We include both positive as well as negative, hence we must include plus minus.
Top left
x = 25
bottom left
x =81
right
x =17
