All categories

2 years ago

I need help fast please

Mathematics

1 answer:

Mademuasel [1]2 years ago

5 0

306 cause 2448divided by 8

You might be interested in

What is 9 3/10- 5 7/10 equal

Scorpion4ik [409]

T\The answer would be 3 6/10, or 3.6.

3 0

3 years ago

Problem 2.2

lana [24]

Answer:

$3.60.

Step-by-step explanation:

4.5 = x + 20% of x

4.5 = x + 0.2x

1.2x = 4.5

x = 3.75

6 0

2 years ago

Anyone have an idea?

Phantasy [73]

Answer:

yes I have an idea jnhvhbvcf

7 0

3 years ago

Read 2 more answers

A teenager who is 5 feet tall throws an object into the air. The quadratic function LaTeX: f\left(x\right)=-16x^2+64x+5f ( x ) =

tia_tia [17]

Answer:

At approximately x = 0.08 and x = 3.92.

Step-by-step explanation:

The height of the ball is modeled by the function:

$f(x)=-16x^2+64x+5$

Where f(x) is the height after x seconds.

We want to determine the time(s) when the ball is 10 feet in the air.

Therefore, we will set the function equal to 10 and solve for x:

$10=-16x^2+64x+5$

Subtracting 10 from both sides:

$-16x^2+64x-5=0$

For simplicity, divide both sides by -1:

$16x^2-64x+5=0$

We will use the quadratic formula. In this case a = 16, b = -64, and c = 5. Therefore:

$\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

Substitute:

$\displaystyle x=\frac{-(-64)\pm\sqrt{(-64)^2-4(16)(5)}}{2(16)}$

Evaluate:

$\displaystyle x=\frac{64\pm\sqrt{3776}}{32}$

Simplify the square root:

$\sqrt{3776}=\sqrt{64\cdot 59}=8\sqrt{59}$

Therefore:

$\displaystyle x=\frac{64\pm8\sqrt{59}}{32}$

Simplify:

$\displaystyle x=\frac{8\pm\sqrt{59}}{4}$

Approximate:

$\displaystyle x=\frac{8+\sqrt{59}}{4}\approx 3.92\text{ and } x=\frac{8-\sqrt{59}}{4}\approx0.08$

Therefore, the ball will reach a height of 10 feet at approximately x = 0.08 and x = 3.92.

7 0

2 years ago

Number 8 please! It's urgent

kykrilka [37]

T chart but thats all i can think of

3 0

2 years ago