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crimeas [40]
3 years ago
14

10 x 1/2 + (-6) (-3)

Mathematics
1 answer:
torisob [31]3 years ago
5 0
Equation

10x1/2+(-6) (-3)

Answer

23
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Name _____________________________________ Date ______________________________Pd______ Unit: Equations & Inequalities Homewo
valentina_108 [34]
Pauline eunice m deguzman
5 0
3 years ago
Find the equation of the line using the given information.
Alecsey [184]

When the slope is zero, the line is horizontal. Its equation will be of the form

... y = constant

The y-value of your point is specified as -9, so the equation of the line through that point is

... y = -9

8 0
4 years ago
Y=x+2 2x-y=-4 Solve the systems of equations
larisa86 [58]

Answer:

Step-by-step explanation:

Given that,

y=x+2 equation 1

2x-y=-4 equation 2

This is a simultaneous equation.

Substitute equation 1 into equation 2

2x-y=-4. Since y=x+2

2x-(x+2) = -4

2x-x-2 = -4

x-2 = -4

x = -4+2

x = -2

Also from equation 1

y=x+2

Since x=-2

y=-2+2

y=0

Then, solution (x, y) = (-2,0)

4 0
3 years ago
Read 2 more answers
There are 52 playing cards in a standard deck of cards. If Patrica selects a card at random, what is the probability that it wil
Alisiya [41]
Since there are two black queens out of 52 cards, there is a 2/52 chance of drawing a black queen first.  This is equivalent to a 1/26 chance.

Now that we have removed a black queen, there are 51 cards left in the deck.  26 of them are red because we only took away a black card.  This means that there is a 26/51 of drawing a red card next.

In order to find the probability of both of these happening, we multiply the two together.  1/26 * 26/51 = 26/1326.  This reduces to 1/51.  So, there is a 1/51 chance of drawing a black queen, then a red card.
8 0
3 years ago
If log 5 = p and log 2=q then log 200 can be written in terms of p and q as?
Andrei [34K]
<h3>Answer:  2p + 3q</h3>

Work Shown:

log(200) = log(2^3*5^2)

log(200) = log(2^3) + log(5^2)

log(200) = 3*log(2) + 2*log(5)

log(200) = 3*q + 2*p

log(200) = 2p + 3q

The log rules I used were

log(A*B) = log(A)+log(B)

log(A^B) = B*log(A)

8 0
3 years ago
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