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zavuch27 [327]
3 years ago
14

I need help with Problem 3 and The problem has to be explained

Mathematics
1 answer:
Marat540 [252]3 years ago
7 0
I'm sorry, I don't see the question. Could you please retake the photo in better quality so I could answer it? Thanks!
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The discounted price of a book is 85% of the original price. This is a savings of $3. A sales tax of 8% will be added to the dis
Ad libitum [116K]
I think the sales tax is $0.28 cents
4 0
3 years ago
Which are correct representations of the inequality –3(2x – 5) < 5(2 – x)? Select two options.
chubhunter [2.5K]

The correct statements are options C and option D.

  • - 6x + 15 < 10 - 5x ⇒ 3rd answer
  • An open circle is at 5 and a bold line starts at 5 and is pointing to the right.
<h3 /><h3>What is inequality?</h3>

The relation between two expressions that are not equal, employing a sign such as ≠ ‘not equal to’, > ‘greater than, or < ‘less than.

The inequality is -3(2x - 5) < 5(2 - x)

At first, simplify each side

-3(2x - 5) = -3(2x) + -3(-5)

Remember (-)(-) = (+)

-3(2x - 5) = - 6x + 15

5(2 - x) = 5(2) + 5(-x)

Remember (+)(-) = (-)

5(2 - x) = 10 - 5x

- 6x + 15 < 10 - 5x

Subtract 15 from both sides

- 6x < -5 - 5x

Add 5x to both sides

- x < - 5

Remember the coefficient of x is negative, then when you divide both sides by it you must reverse the sign of inequality

The coefficient of x is -1

Divide both sides by -1

x > 5

Therefore the correct statements are options C and option D.

  • - 6x + 15 < 10 - 5x ⇒ 3rd answer
  • An open circle is at 5 and a bold line starts at 5 and is pointing to the right.

To know more about inequality follow

brainly.com/question/24372553

#SPJ1

4 0
2 years ago
(a^2 - b^2)=???????????????????????????
Gekata [30.6K]

(a^2 - b^2) = (a + b)(a - b)

6 0
3 years ago
Write 5 to the power of 8 as a quotient of two exponential terms with the same base in four different ways. use negative or zero
ryzh [129]
So, we are given 5^8. It was happy and content. But then... we had to write it as a quotient of two exponential terms with the same base in four different ways and use negative or zero exponents and ahhhhhh!!!

... anyways...

We'll build a quotient of two exponential terms with the same base 5. Something like this:

5^a / 5^b

We need them to make 5^8 when we are done. I'll first use a zero exponent.

[1] Now, zero exponents are nice since they make things equal 1. Like 5^0 = 1. Well, obviously, 5^8 / 1 = 5^8. So, our first quotient can be:

5^8 / 5^0

Done.

[2] Let's try this on its head. This one's a little weird. Remember that negative exponents flip things upside down. So 5^-8 = 1/5^8    and   1/5^-8 = 5^8 for example. In fact... that's the answer!

5^0 / 5^-8 = 5^8

Done.

[3] Let's try to not use 0s or 8s. We can be clever and do something like this:

5^-1 / 5^-9

What the heck is that? Well, we just flip them and get:

5^-1 / 5^-9 = 5^9 / 5^1 = 5^8

Done.

[4] Can you come up with one last trick on your own? Try it!
3 0
4 years ago
The length of a square is increased by 2 inches. The perimeter of the original square is ten inches more than the length of one
Lapatulllka [165]
Let x be the length of one side of the smaller square
Let y be the length of one side of the larger square
4x would be the perimeter of the smaller square, as it has 4 sides
Therefore 4x = y + 10, as the perimeter of the smaller square is 10 inches bigger than one side of the larger square.
We're going to solve this question using simultaneous equations. This means we need another equation to compare the first one to.
Since we know that one side of the larger square is 2 inches bigger than the first one, we can make the equation
y = x + 2
Know that we know the value of y in terms of x, we can introduce this value to the original equation to find:
4x = (x + 2) + 10
Therefore:
4x = x + 12
3x = 12
x = 4
Now that we know the size of the sides on the smaller square, we can figure out the size of the larger square by using our second equation (y = x + 2)
y = 4 + 2
y = 6
Therefore, the length of each side of the larger square is<u> B.6</u>
4 0
3 years ago
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