2/9 of the students in a school are in sixth grade.

Which represents the series 1+1/3+1/9+1/27 using sigma notation?

Zina [86]

$\displaystyle 1+ \frac{1}{3} + \frac{1}{9} + \frac{1}{27} = \frac{1}{3^0}+ \frac{1}{3^1}+ \frac{1}{3^2} + \frac{1}{3^3} =\left( \frac{1}{3}\right)^0+\left( \frac{1}{3}\right)^1+\left( \frac{1}{3}\right)^2+\\\\\left( \frac{1}{3}\right)^3=\sum_{x=0}^3\left( \frac{1}{3}\right)^x \, \text{or }\, \sum_{i=1}^4\left( \frac{1}{3}\right)^{i-1}$

6 0

3 years ago

REwaRDiNG BRAINLY TO CORRECT

vfiekz [6]

Answer:

54 millimeters

Step-by-step explanation:

The median length would be in the middle of the values in order, so you could order the numbers 50,50,52,53,54,55,55,55,57. You would then find the middle value which would be the 5th value in a list of 9. In this case, it would be 54 millimeters.

6 0

3 years ago

Read 2 more answers

The question is bellow

frozen [14]

Answer:

20

Step-by-step explanation:

we expect to have the smae outcome so we just multiply the out puts by 5 to see what would happen after 125 draws

8 0

2 years ago

F (x)-x^2+6x-7 at x=2

Nitella [24]

Consider the vertex form of the parabola.y=a(x+h)2+ky=a(x+h)2+kRewrite the function in terms of xx and yy.y=x2+6x−7y=x2+6x-7Complete the square on the right side of the equation.(x+3)2−16(x+3)2-16Reorder the right side of the equation to match the vertex form of a parabola.y=(x+3)2−16y=(x+3)2-16Since 33 does not contain the variable to solve for, move it to the right side of the equation by subtracting 33 from both sides.x=−3x=-3Use the vertex form, y=a(x−h)2+ky=a(x-h)2+k, to determine the values of aa, hh, and kk.a=1a=1h=−3h=-3k=−16k=-16Since the value of aa is positive, the parabola opens up.Opens UpFind the vertex (h,k)(h,k).(−3,−16)(-3,-16)Find pp, the distance from the vertex to the focus.1414Find the focus.(−3,−634)(-3,-634)Find the axis of symmetry by finding the line that passes through the vertex and the focus.x=−3x=-3Find the directrix.y=−654y=-654Use the properties of the parabola to analyze and graph the parabola.Direction: Opens UpVertex: (−3,−16)(-3,-16)Focus: (−3,−634)(-3,-634)Axis of Symmetry: x=−3x=-3Directrix: y=−654

I sorta shortened the steps a bit if you need me to explain any more steps I will just ask.
I am sure you probably went over some of this in your class that is why I skipped a few steps so you would at least learn a little bit hehe.

I really hope this helps you.

7 0

3 years ago

The sequence -1, 1, -1, 1 and so on is

S_A_V [24]

Answer:

-1 is the next one ithink

6 0

3 years ago