<span>a) Differentiate both sides of lnq − 3lnp + 0.003p=7 with respect to p, keeping in mind that q is a function of p and so using the Chain Rule to differentiate any functions of q:
(1/q)(dq/dp) − 3/p + 0.003 = 0
dq/dp = (3/p − 0.003)q.
So E(p) = dq/dp (p/q) = (3/p − 0.003)(q)(p/q) = (3/p − 0.003)p = 3 − 0.003p.
b) The revenue is pq.
Note that (d/dp) of pq = q + p dq/dp = q[1 + dq/dp (p/q)] = q(1 + E(p)), which is zero when E(p) = −1. Therefore, to maximize revenue, set E(p) = −1:
3 − 0.003p = −1
0.003p = 4
p = 4/0.003 = 4000/3 = 1333.33</span>
Answer:
it should be 10.4 in 6 years.
Step-by-step explanation:
not sure what you were asking.
Problem 1
subtract 3 x
5y=-3x+11
divide 5
y=3/5x+2.2'
Problem 2
add 5x
7y=5x+9
divide 7
y=5/7x+1.3'
'notice'
you can put 2.2 into a fraction (11/5) and 1.3 (9/7) if your teacher allows it, but i put them into decimals
Answer: I think your answer would be B
i hope it's right
Answer:
15
Step-by-step explanation:
z2 - 2z + 15
(15)2 - 2(15) + 15
30 - 30 + 15
0 + 15
15
