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Anna [14]
3 years ago
11

Nine square tiles are laid out on a table so that they make a solid pattern. perimeters of the fiques that you can be formed?

Mathematics
1 answer:
Anastasy [175]3 years ago
6 0
Let the side of one square be x.
The maximum perimeter will be when the squares will be lined end to end.
This will be:
x + 9x + 9x + x
= 20x

The perimeter of the figures formed will be less than or equal to 20x.
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The sum of three consecutive integers is 261 , which equation could be used to find the integer .
Allisa [31]

Answer:

You got it wrong, its the first option

Step-by-step explanation:

Since its not asking for a consectuive EVEN or ODD integer its not

X + X+2 + X+4...

Instead its just the normal way

X + X+1 + X+2 + X+3....

SO thats the correct answer.

4 0
3 years ago
Find the accumulated value of an investment of $ 20 comma 000 for 4 years at an interest rate of 6.5 % if the money is a. compou
MA_775_DIABLO [31]
Brainly suggestions is being a listener
7 0
3 years ago
What’s distributive property to express 36+16
Gennadij [26K]

Factors of 36 are 18,12,9,6,4,3,2,1

The common factor of 16 and 36 are 4,2,1

5 0
2 years ago
3. Try It #3 Write the point-slope form of an equation of a line with a slope of -2 that passes through the point (-2,2). Then r
vova2212 [387]

Answer:

Point-slope form of equation given as $y-2=-2(x+2)$.

Slope-intercept form of equation is given as $y=-2 x-2$.

Step-by-step explanation:

In the question, it is given that the slope of a line is -2 and it passes from (-2,2).

It is asked to write the point-slope form of the equation and rewrite it as slope-intercept form.

To do so, first find the values which are given in the question and put it in the formula of point-slope form. Simplify the equation to rewrite as slope-intercept form.

Step 1 of 2

Passing point of the line is (-2,2).

Hence, $x_{1}=-2$ and

$$y_{1}=2 \text {. }$$

Also, the slope of the line is -2.

Hence, m=-2

Substitute the above values in point-slope form of equation given by $y-y_{1}=m\left(x-x_{1}\right)$

$$\begin{aligned}&y-y_{1}=m\left(x-x_{1}\right) \\&y-2=-2(x-(-2) \\&y-2=-2(x+2)\end{aligned}$$

Hence, point-slope form of equation given as y-2=-2(x+2).

Step 2 of 2

Solve y-2=-2(x+2) to write it as slope-intercept form given by y=mx+c.

$$\begin{aligned}&y-2=-2(x+2) \\&y-2=-2 x-4 \\&y=-2 x-4+2 \\&y=-2 x-2\end{aligned}$$

Hence, slope-intercept form of equation is given as y=-2x-2.

7 0
2 years ago
I need the help on this
Salsk061 [2.6K]

Answer:

Go catipiller

Step-by-step explanation:

8 0
2 years ago
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