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Anna [14]
3 years ago
11

Nine square tiles are laid out on a table so that they make a solid pattern. perimeters of the fiques that you can be formed?

Mathematics
1 answer:
Anastasy [175]3 years ago
6 0
Let the side of one square be x.
The maximum perimeter will be when the squares will be lined end to end.
This will be:
x + 9x + 9x + x
= 20x

The perimeter of the figures formed will be less than or equal to 20x.
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Each of a sample of four home mortgages is classified as fixed rate (F) or variable rate (V). (Enter your answers as a comma-sep
omeli [17]

Answer:

a)

{FVVV,FFVV,VFVV,VVVV,FVFV,FFFV,VFFV,VVFV,FVVF,FFVF,VFVF,VVVF,FVFF,FFFF,VFFF,VVFF}

b)

{FFFV,FFVF,FVFF,VFFF}

c)

{FFFF,VVVV}

d)

{FFFV,FFVF,FVFF,FFFF,VFFF}

e)

{FFFV,FFVF,FVFF,FFFF,VFFF,VVVV}

{FFFF}

f)

{FFFV,FFVF,FVFF,VFFF,FFFF,VVVV}

{ }

Step-by-step explanation:

a)

The 16 outcomes for a sample of four home mortgages classified as fixed and variable rate are

Sr.No Outcomes

1          FVVV

2         FFVV

3         VFVV

4         VVVV

5         FVFV

6         FFFV

7         VFFV

8         VVFV

9         FVVF

10        FFVF

11         VFVF

12        VVVF

13        FVFF

14        FFFF

15        VFFF

16        VVFF

b)

Let A be the event that exactly three are fixed rate. Thus, event A consists of following outcomes

A={FFFV,FFVF,FVFF,VFFF}

c)

Let B be the event that all four are of same type. The event B consists of either all fixed rate or all variable rate. Thus, event B consists of following outcomes

B={FFFF,VVVV}

d)

Let C be the event that at most one of four is variable rate. The event C consists of less than and equal to one variable rate. Thus, event C consists of following outcomes

C={FFFV,FFVF,FVFF,FFFF,VFFF}

e)

Let union of part(c) and part(d) can be represented as BUC. The union represents all the outcomes in event B and event C.

B∪C={FFFF,VVVV}∪{FFFV,FFVF,FVFF,FFFF,VFFF}

B∪C={FFFV,FFVF,FVFF,FFFF,VFFF,VVVV}

Let intersection of part(c) and part(d) can be represented as B∩C. The intersection represents the common outcomes in event B and event C.

B∩C={FFFF,VVVV}∩{FFFV,FFVF,FVFF,FFFF,VFFF}

B∩C={FFFF}

f)

Let union of part(b) and part(c) can be represented as AUB. The union represents all the outcomes in event A and event B.

A∪B={FFFV,FFVF,FVFF,VFFF}∪{FFFF,VVVV}

A∪B={FFFV,FFVF,FVFF,VFFF,FFFF,VVVV}

Let intersection of part(b) and part(c) can be represented as A∩B. The intersection represents the common outcomes in event A and event B.

A∩B={FFFV,FFVF,FVFF,VFFF}∩{FFFF,VVVV}

A∩B={ }

So intersection of part(b) and part(c) is an empty set as there is no common outcome in these two sets.

8 0
3 years ago
Show steps solving this problem 173×797=
Contact [7]
If the problem is
 (17 ^ 3) * (79 ^ 7) 
 The steps are: 
 Step 1:
 (17 ^ 3) = 4913
 Step 2:
 (79 ^ 7) = 1.92039E + 13
 Step 3:
 (4913) * (1.92039E + 13) = 9.43488E + 16

 If the problem is 
 (173) * (797)
 Step 1: 
 Multiply both terms with a calculator:
 (173) * (797) = 137881
8 0
2 years ago
Sandra used partial products to find the product of 438 × 17 by multiplying 438 by 1 and 438 by 7 to get 3,066. Find the product
boyakko [2]

Let us determine the product of 438 and 17 by partial products.

Consider 438 = 400+30+8

and 17 = 10+7

So, 438 \times 17 = (400+30+8) \times (10+7)

438 \times 17 = (400\times 10)+(30 \times 10)+(8 \times 10) +(400 \times 7)+(30 \times 7)+(8 \times 7)

= 438 \times 17 = (4000+300+80+2800+210+56)

= 7446

Therefore, the product of 438 and 17 is 7446.

No, Sandra's answer is not correct.

Because she should have expressed 17 as (10+7), then if she multiplied (438 by 10) and (438 by 7). And, then added the results.Then her answer would be correct.

6 0
3 years ago
What is the degree of one and a half full turns
anygoal [31]

1turn = 360 half a turn is 180
360+180=540

8 0
3 years ago
What value of k makes the equation k + 4 divided by 0.2 = 5 true?
Anna11 [10]
K=-15
Hope this helps ^^

6 0
3 years ago
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