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3 years ago

30 POINTS NEED HELP ASAP MATH QUESTION A. 19 B. 108 C. 133 D. 763

Mathematics

2 answers:

Oksanka [162]3 years ago

8 0

Answer:

Step-by-step explanation:

We know, that looking from Solid #1, there is 192 M&M's. Since the width is 4 cm, and the length is 5 cm, and the height is 4 cm, we know that with a square of length and width of 7cm, and a height of 6.5, it would have a larger volume, and would hole more M&M's. Which means...

we could eliminate options A), B), and C),

Which leaves us with D).

Hope this helps...

allsm [11]3 years ago

4 0

Answer:

I believe the answer is d because it couldn't be any smaller than either box.

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An apple grower finds that if he plants 80 trees per acre, each tree will yield 26 bushels of fruit. He estimates that for each

hammer [34]

Answer: The maximum revenue is $7482 . To get a maximum yield , The number of trees per acre needed is 43.

Step-by-step explanation:

Solution:

Let x represent the extra tree

So for an additional tree the yield of each tree will decrease by 4 bushels.

(80 +x)(26-4x) by expanding

2080 - 320x +26x -4x^2

Using x= -b/2a

X= 294/ -8

X= - 36.75

So apparently he currently has far too many trees per acre. To get the maximum yield , she needs to reduce the number of trees per acre by 36.75

So the number of trees per acre for maximum yield is

80-36.75

=43.25

Approximately x=43

So by reducing he get extra bushel in the tune of 174.

Total revenue= 174 ×43× 1$

=$7482

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3 years ago

Ms. Jones is ordering pizzas for the school dance. To keep things simple, she plans on only ordering two types, cheese and peppe

Degger [83]

Not 100% sure but i think it is b

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3 years ago

Read 2 more answers

Use the confidence level and sample data to find a confidence interval for estimating the population μ. Round your answer to the

Levart [38]

Answer: Choice A.) 88.2 < μ < 93.0

=============================================================

Explanation:

We have this given info:

n = 92 = sample size
xbar = 90.6 = sample mean
sigma = 8.9 = population standard deviation
C = 99% = confidence level

Because n > 30 and because we know sigma, this allows us to use the Z distribution (aka standard normal distribution).

At 99% confidence, the z critical value is roughly z = 2.576; use a reference sheet, table, or calculator to determine this.

The lower bound of the confidence interval (L) is roughly

L = xbar - z*sigma/sqrt(n)

L = 90.6 - 2.576*8.9/sqrt(92)

L = 88.209757568781

L = 88.2

The upper bound (U) of this confidence interval is roughly

U = xbar + z*sigma/sqrt(n)

U = 90.6 + 2.576*8.9/sqrt(92)

U = 92.990242431219

U = 93.0

Therefore, the confidence interval in the format (L, U) is approximately (88.2, 93.0)

When converted to L < μ < U format, then we get approximately 88.2 < μ < 93.0 which shows that the final answer is choice A.

We're 99% confident that the population mean mu is somewhere between 88.2 and 93.0

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3 years ago

What is the slope and y intercept of the linear equation y=5x-4

Wittaler [7]

The slope is 5
the y intercept is -4

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Firdavs [7]

Check the picture below.

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