I don't know any <em><u>slick</u></em> way to do this. I would just list the prime numbers
between 40 and 50 and test them one at a time.
The prime numbers between 40 and 50 are: 41, 43, 47
<u>Test 41:</u>
-- add 1 . . . 42
-- prime factors of 42 . . . 2, 3, 7
-- sum of the factors . . . 12
<u>Test 43:</u>
-- add 1 . . . 44
-- prime factors of 44 . . . 2, 11
-- sum of the factors . . . 13
<u>Test 47:</u>
-- add 1 . . . 48
-- prime factors of 48 . . . 2, 3,
-- sum of the factors . . . 5
Maybe I'm not understanding how to list prime factors, but so far,
I haven't found any number that answers the question.
Maybe if I write the prime factorization of 44 like this:
44 = 2 * 2 * 11
Now the items in the prime factorization do add up to 15.
So the answer would seem to be <em>43.</em>
Answer:
184
Step-by-step explanation:
One ticket cost 23 (115/5)
23x8
Answer:
11/50
Step-by-step explanation:
The frequency numbers for landing on 1, 2, and 3 are:
25, 53, 62.
We add them up to get: 25 + 53 + 62 = 140
Since 250 spins were made, and 140 of them landed on 1, 2, or 3, then
250 - 140 = 110,
so 110 landed on 4 or 5.
We are told the numbers of spins landing on 4 and 5 are equal, so
110/2 = 55,
so the spinner landed 55 times on 4 and 55 times on 5.
relative frequency = 55/250 = 11/50
Answer:
- definition of angle bisector
Step-by-step explanation:
<u>First step in proof is:</u>
<u>The reason is:</u>
- definition of angle bisector
I think the answer is 59.29,24.2×245%=24.2