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Murljashka [212]
3 years ago
8

Tell the answer plss of this q

Mathematics
1 answer:
pav-90 [236]3 years ago
5 0
2=70
3=110
4=110
Pretty simple
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A train moves from rest to a speed of 40 m/s in 20.0 seconds. What is its acceleration?
alina1380 [7]

Answer: 25m/s

Explanation:

S1=(2u+v)t   \\ =20×20=400m \\ S2=40×20=800m \\ S3=(2u+v)t \\ =20×40=800m \\ Total \:  displacement =2000 m \\ Total  \: time \:  taken =80 m \\ V=802000=25m/s

5 0
4 years ago
Kimmy has 47 ft.² of cement blocks each square block has size 1 foot long what is the greatest perimeter of a rectangle that she
blagie [28]

Answer:

The larges perimeter she can make becomes is 96 ft

Step-by-step explanation:

Here we note that the available brick is 47 ft²

Therefore, she has 47 square cement blocks

Let the length of the sides of the rectangle with the most perimeter be x and y

Then 2·x + 2·y = 47 which is not possible because 47 is a prime number

Hence we have the possible sides of the rectangle is a single line of square blocks such that

x × y  = 47 ft² where y = 1 hence x = 47

The larges perimeter she can make becomes, 2 × (1 + 47) = 96 ft.

3 0
4 years ago
A line contains the points (4, 2) and (0, -1). What is the equation of the line?
Monica [59]

Answer:

4x3y

Step-by-step             hmmm ask your teacher

4 0
3 years ago
Find the LCM (least common multiple) of 25 and 35.<br><br> LCM =
Paladinen [302]
  • <em>Answer:</em>

<em>175</em>

  • <em>Step-by-step explanation:</em>

<em>Hi there ! </em>

<em>25 = 5²</em>

<em>35 = 5×7</em>

<em>Lcm = multiply together each of the prime numbers with the highest power</em>

<em>Lcm(25 ; 35) = 5²×7 = 25×7 = 175</em>

<em>Good luck !</em>

5 0
4 years ago
Can someone please help me I will be giving 100 points and 5 starts if you can help me
svlad2 [7]

Answer:

number 5 is 15x

Step-by-step explanation:

what you have to do is just add basically. The ones with exponents you do the usual with those as well. Ignore the X's and when you solve the problem add the x beside the number.

4 0
3 years ago
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