-1/4*x^2-x+3=-1/4*(x^2+4x)+3=-1/4*(x^2+4x+4)+4=-1/4*(x+2)^2+4
x0=-2
Answer:
4) 7a + 11b
5) i'm not sure
6) 3 (n = 3)
7) i can't see the last ones, but i know that y = 6
i hope this helps
sorry i can't help more :(
Have a great day!
Your givens are A+S=326 and 8A+5S=1972.
A+S=326
-S -S
A=326-S
if you substitute this into the other equation that you are given it looks like this
8(326-S)+5S=1972.
After this we use PEMDAS to solve for S
2608-8S+5S=1972
2608-3S=1972
-3S=(-636)
-S=(-212)
S=212
If we know S=212 we can go back and solve the origonal equation for A.
A+212=326
A=114
Answer:
ans=(-2,2)
Step-by-step explanation:
let the end point of circle diameter (-1,5) and (3,-1) be (x1,y1) and (x2,y2) respectively
using mid point formula
(x,y)=(-1,5)/2+(-3,-1)/2 [center point is equal to mid point of diameter)
= (-1+(-3))/2+(5-1)/2
=(-2,2)
center coordinate of circle=(-2,2)
Answer:
31
Step-by-step explanation:
12-21+6+3+4-7+6
31
