Hello!
To solve this, first assume all the coins are $1. Then, find the value that would have. 1 * 21 = $21.
Now, see how far away from $30 we are. 30 - 21 = 9. Therefore, we need an increase by $9.
For each coin changed from a $1 to a $2, how much of an increase is there? $1. Therefore, change 9 coins to $2 coins to have an increase of $9. If he has 9 $2 coins, he'll have 21 - 9 $1 coins, or 12.
Therefore, your final answer is 12 $1 coins and 9 $2 coins.
Hope this helps!
Answer:
A,C,D
Step-by-step explanation:
Answer:
1.5871
Step-by-step explanation:
According to the Question,
- we have, 7 log(15/16)+6log(8/3)+5log(2/3)+log(32/25)
The Solution, With Basic Properties of Log.
7*log15-7*log16+6*log8-6*log3+5*log2-5*log3+log32-log25
7*1.176-7*1.204+6*0.903-6*0.477+5*0.3010-5*0.477+1.505-1.3979
on Solving, We get
1.5871
Oof actually IDK the answer. I can't figure it out. I got the answer 1,344 but I'm sure that's not right. I'm so sorry! :(
Plug the y value in for y and plug the x value in for x
> less than
<u>></u> less than or equal to
Example:
(4,5)
y > 5y <u>></u> x
5 > 5x5 <u>></u> 4 = 5 > 25 <u>></u> 4 = false
they all should be false
if one had to be correct, I would say (0, 0)
