Answer:
The correct Answer is 0.0571
Explanation:
53% of U.S. households have a PCs.
So, P(Having personal computer) = p = 0.53
Sample size(n) = 250
np(1-p) = 250 * 0.53 * (1 - 0.53) = 62.275 > 10
So, we can just estimate binomial distribution to normal distribution
Mean of proportion(p) = 0.53
Standard error of proportion(SE) = 
= 
= 0.0316
For x = 120, sample proportion(p) = 
= 
= 0.48
So, likelihood that fewer than 120 have a PC
= P(x < 120)
= P( p^ < 0.48 )
= P(z < 
) (z=
)
= P(z < -1.58)
= 0.0571 ( From normal table )
Answer:
1. active listening 8. an online journal
2. barrier 1. a strategy for showing other people you are interested in what they are saying and that you understand what they are saying and how they feel about it
3. blog 2. anything that interferes with a message being sent or received
4. communication 5. guidelines for courteous electronic communication
5. netiquette 7. the person who creates or composes a message and delivers it either orally or in writing
6. receiver 9.. a personal belief that one should work hard and do a good job
7. sender 3. an online database of Web pages that can be created or edited by anyone (with permission)
8. wiki 6. the person who receives a message
9. work ethic 4. an exchange of information
Explanation:
The answer is as mentioned above. And these are important words from subject Professional Communication. And like when we talk of an exchange of information, we mean communication. And similarly, other words means as being mentioned above.
integer userInput
integer i
integer mid
integer array(20) number
userInput = 1
for i = 0; userInput >= 0; i = i + 1
if number[i] > -1
userInput = Get next input
number[i] = userInput
i = i - 1
mid = i / 2
if i > 9
Put "Too many inputs" to output
elseif i % 2 == 0
Put number[mid - 1] to output
else
Put number[mid] to output
