Cells are combined in a structure called tissue wich have the same properties like the cells wich are formed by.
Answer No 4:
The possible gametes for a homozygous grey furred and homozygous black eyed rabbit will be GGBB.
Answer No 3:
The possible gametes for a heterozygous grey furred and heterozygous black eyed rabbit will be GgBb.
Answer No 4:
The possible gametes for a heterozygous grey furred and red eyed rabbit will be Ggbb.
Answer No 5:
The possible gametes for a white furred and heterozygous black eyed rabbit will be ggBb.
On sooory I send u answer in msg
Answer:
There was no sulfur compound added to the medium, that could be used as an electron donor.
Explanation:
Bacteria that use light for energy requirements mean that they get their energy from photosynthesis and transferring energy through the molecules.
Bacteria play a major part in the reductive and oxidative cycle of the sulfur which is mediated by the help of photosynthetic bacteria, so the sulfur or sulfur compounds are major requirements for their growth in the habitat or the medium.
Thus, the correct answer would be- There was no sulfur compound added to the medium, that could be used as an electron donor.
<span> Basically the male will have CC, the hen will have cc, and neither of them will have I. The key thing is that _all_ the chicks are coloured.
The male must have at least 1 C to be coloured, and cannot possess the dominant I. The hen has cc and/or an I to not be coloured.
That one chick is coloured would tell you little - only that the hen couldn't have 2 inhibitor alleles because otherwise the chick would have to have one and it doesn't.
However, for all of many chicks to be coloured, that means that the hen can't have any inhibitor alleles (otherwise around 50% would be white for that reason alone).
So to be colourless, the hen must be cc. However, if the male had only 1 colour allele (ie it was Cc) that would still mean that 50% of the chicks would be Cc (daddy's 'c' and one of mummy's 'c's).
Hope this helps please award brainly :)
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