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nekit [7.7K]
2 years ago
12

What is the value of y in the equation 6.4x + 2.8y = 44.4, when x = 3

Mathematics
2 answers:
Georgia [21]2 years ago
7 0

Answer:

9

Step-by-step explanation:

6.4(x)+2.8y=44.4

6.4(3)+2.8y=44.4

19.2+2.8y=44.4

2.8y=25.2

y=9

lara31 [8.8K]2 years ago
3 0

Answer:

y=9

Step-by-step explanation:

plus in the 3 into x and move the constant to the right. go ahead and calculate then divide by both sides. you should end up with y=9

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Answer:

Deal B is better

Step-by-step explanation:

over a year in payment Deal b will be less

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3 years ago
you have a piece of yarn that is 12 1/2 ft long. You need to cut it into strips that are 1 1/4 ft long. how many strips will you
zysi [14]

Answer:

A.

Step-by-step explanation:

12.5/10=1.25.

12.5/8=1.56

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it's important to know what 1/2 is, 1/3 is, 1/4 is and 1/5 it's also important to know things like 2/2, 2/3, 3/3, 2/4, 3/4, 4/4, 2/5, 3/5, 4/5, and 5/5. You don't need this until 8th grade though. But get on it if you can. Ask your parents or teacher.

5 0
3 years ago
Find the modulus of the complex number 6-2i
Papessa [141]

Answer:

The modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

Step-by-step explanation:

Given the number

6-2i

We know that

z = x + iy

where x and y are real and \sqrt{-1}=i

The modulus or absolute value of z is:

|z|\:=\sqrt{x^2+y^2}

Therefore, the modulus of 6-2i  will be:

z=6-2i

z=6+(-2)i

|z|\:=\sqrt{x^2+y^2}

|z|\:=\sqrt{6^2+\left(-2\right)^2}

    =\sqrt{6^2+2^2}

    =\sqrt{36+4}

    =\sqrt{40}

    =\sqrt{2^2}\sqrt{2\cdot \:5}

    =2\sqrt{2\cdot \:5}

   =2\sqrt{10}

Therefore, the modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

3 0
3 years ago
Please help i am confused
son4ous [18]

Answer: (4)

Step-by-step explanation:

The parts listed in the congruence statements don't correspond, so they aren't necessarily congruent.

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2 years ago
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valkas [14]
50 the answer is most likely 50
6 0
3 years ago
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