Answer:
out of 250 wala nagka crush sayo hshshs
charot lng
The class starts out with 26 students, of whom 12 are girls and, perhaps unlike Mr Morris, are sure of it.
The probability of the first random choice being a girl is 12/26. If successful, there are now 25 students left, of whom 11 are girls. The probability of a girl on the 2nd random choice is 11/25. The probability that BOTH random choices are successful is (12/26) x (11/25). That's (132/650), or about 20.31% (rounded).
Answer:
K = 151.9422481
Step-by-step explanation:
At the end of year 10, your perpetuity is worth 100/i
(1) is worth 90×s_{10%i}
So if you set them equal you get 90*[(1+i)^10 - 1]/i = 100/i or [(1+i)^10 - 1] = 10/9 or (1+i)^10 = 19/9 or i = 0.077583937
So now the question compare (1) to (2), at t = 0
(1) is worth 90×a_{10%i} = 90(1 - 1/(1.077583937)^10)/0.077583937 = 610.5441743
(2) is worth K×a_{5%i} = 4.018264714×K
Therefore K = 151.9422481
Answer:
n^2 + 2n.
Step-by-step explanation:
n = 1 2 3 4 5
term t = 3 8 15 24 35
Diffs = 5 7 9 11
2 2 2 - so the nth term contains n^2.
n^2 = 1 4 9 16 25
t - n^2 = 2 4 6 8 10
This is an arithmetic sequence with nth term = 2 + (n-1)2 = 2n
So the nth term of the quadratic sequence = n^2 + 2n.
