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gulaghasi [49]
3 years ago
5

If perry is late for work 4% of the time and his boss is 8% of the time what is the probability that both will be late

Mathematics
1 answer:
Taya2010 [7]3 years ago
6 0

Answer:is do not know

Step-by-step explanation:

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The mean time it takes to walk to the bus stop is 8 minutes (with a standard deviation of 2 minutes) and the mean time it takes
kifflom [539]

We have been given for a normal distribution the mean time it takes to walk to the bus stop is 8 minutes with a standard deviation of 2 minutes. And the mean time it takes for the bus to get to school is 20 minutes with a standard deviation of 4 minutes.

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(b) Standard deviation of the trip to school can be found as:

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Therefore, standard deviation of the entire trip is 4.47 minutes.

(c) Let us first find z score corresponding to 30 minutes.z=\frac{x-\mu }{\sigma }=\frac{30-28}{4.47}=0.447

We need to find the probability such that P(x>30)=P(z>0.447)=0.67

Therefore, the required probability is 0.67.

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(e) Standard deviation won't change it will remain 4.47

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z=\frac{x-\mu }{\sigma }=\frac{30-90}{4.47}=0

P(x>30)=P(z>0)=0.5

Therefore, probability will be 0.50.


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3 years ago
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Scale Factor (K) = (new length/measure)/ (original length/measure)
for x-coordinate  = 8/2 = 4
for y-coordinate  = 16/4 = 4

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