16xy, 24x^2y^2 are two expressions with gcf of 8xy.
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7 7/8
= [ (8*7) + 7 ] / 8
= (56 + 7) / 8
=63 / 8
similarly,
3 1/4
=[ (4*3) + 1] / 4
= (12 + 1) / 4
= 13/4
----------------------------
now put the values
7 7/8 - 3 1/4
= 63/8 - 13/4
here, take LCM of 8 & 4 which is 8.
now,
[ (1*63) - (2 * 13) ] / 8
= (63 - 26) / 8
= 37/8
= 4 5/8........................[ here, divide 37 by 8 which gives reminder as 5 and divisible value as 4 ]</span>
A is the answer to your question
I believe A=2 and B=6, sorry if I’m wrong
Answer:
We can reject the hypothesis at the 0.05 significance level.
Step-by-step explanation:
given that an urn contains a very large number of marbles of four different colors: red, orange, yellow, and green. A sample of 12 marbles drawn at random from the urn revealed 2 red, 5 orange, 4 yellow, and 1 green marble.
H0: All colours are equally likely
Ha: atleast two colours are not equally likely
(Two tailed chi square test at 5% significance level)
color Red Orange Yellow Green total
Observed O 2 5 4 1 12
Expected E 3 3 3 3 12
(O-E)^2/E 0.3333 5.3333 0.3333 5.3333 11.3333
chi square = 11.3333
df =3
p value = 0.010055
Since p < 0.05 we reject H0
We can reject the hypothesis at the 0.05 significance level.
