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defon
3 years ago
5

kelly travels at an average rate of 12 miles per hour. she believes she will be able to travel 5.75 miles is 30 minutes can she?

Mathematics
1 answer:
Darya [45]3 years ago
4 0
Yes half of twelve is 6 and 6 miles is more than 5.75 miles
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Can someone help me with this plz
Naily [24]

A. 3n + 4

First Four Terms: 7, 10, 13, 16

Tenth Term: 34:

Plug in 10, 3 x 10 = 30 + 4 = 34

B. 4n - 5

First Four Terms: -1, 3, 7, 11

Tenth Term: 35

Plug in 10, 4 x 10 = 40 - 5 = 35

3 0
3 years ago
After you find the solution, how would you check to make sure your answer is correct?
krek1111 [17]

Answer:

Plug in your variables value.

Step-by-step explanation:

For your case, plug in -6 into the y slot

12(5+2y)= -(6-9y) +4y

12(5+2x-6)= -(6-9x-6)+4y see if that works!

5 0
3 years ago
Read 2 more answers
A biologist found a system of equations to help her calculate the growth of bacteria. The functions she found y=2x2−15y=2x2-15 &
Nesterboy [21]
Part A.
The set of equations can be solved by substitution. Use the expression one equation gives for y as the value of y in the other equation. This gives
  2x²-15 = 3x-6
Subtracting the right side gives a quadratic in standard form that can be solved by any of several methods.
  2x² -3x -9 = 0
  (2x+3)(x-3) = 0 . . . . factor the above equation
  x = -3/2, x = 3 . . . . .use the zero product rule to find x
Now, these x-values can be substituted into either equation for y. The linear equation is often easier to evaluate.
  y = 3(-3/2) -6 = -10.5
  y = 3(3)-6 = 3

The solutions to the system are (-1.5, -10.5) and (3, 3).


Part B.
The two equations can be graphed. The solutions are where the graphs intersect. The graphs intersect where the (x, y) values that satisfy one equation are the same (x, y) values that satisfy the other equation. Those points of intersection are (-1.5, -10.5) and (3, 3).

6 0
3 years ago
An employee shreds 341 pages in 11 minutes of work. How many pages will she shred in 20 minutes?
gavmur [86]

We have been given that an employee shreds 341 pages in 11 minutes of work.

First of all we will divide 341 by 11 to find number of pages shred by employee in one minute.

\text{Pages shred by employee in one minute}=\frac{341}{11}=31

Now let us multiply 31 by 20 to find number of pages shred by employee in 20 minutes.

\text{Pages shred by employee in 20 minutes}=31\cdot20=620

Therefore, employee will shred 620 pages in 20 minutes.

6 0
3 years ago
Pleaseeee help with all
Hatshy [7]

1. 8p-3=13

+3

8p=16      /8

p=2

2. 8j -5 +j=67

==            9j=72    /9

j=8

3.   3(2x-5)=4x+33   <--- =expand ()

6x-15=4x+33      ---> 2x=48

x=24

4. c=b-bx

get just x's on one side

c-b=bx

divide by b---> (c-b)/b=x

6 0
3 years ago
Read 2 more answers
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