Ask question

Ask question

All categories

3 years ago

14

Peaches are being sold for $2 per pound. If x represents the number of pounds of peaches bought and y represents the total cost

of the peaches, which best describes the values of x and y?

2 answers:

Mama L [17]3 years ago

8 0

2X=Y

2 because it is two dollars per pound.

mestny [16]3 years ago

5 0

Answer:

The values of both x and y will be real numbers greater than or equal to 0.

Step-by-step explanation:

You might be interested in

Meg plotted the graph below to show the relationship between the temperature of her city and the number of sweaters sold at a st

makvit [3.9K]

Answer:

please put in the graph

7 0

2 years ago

Help!!!!!! Quick <br> Evaluate (x + y)° for x = -3 and y = 5.<br> - 1/2<br> 2<br> 1<br> O

MrMuchimi

Answer:

it is 1

Step-by-step explanation:

The power of 0 causes all numbers to negate to 1.
Anything to the power of 0 is 1

For example:

(10)^0 = 1

7 0

1 year ago

I need help please thanks!

Natasha_Volkova [10]

Answer:

f=39

Step-by-step explanation:

hi! first, we can multiply by 12 on both sides to eliminate the 12 in the denominator.

f+3= (7/2)*12

f+3=84/2

f+3=42

now, subtract 3 on both sides.

f=39

7 0

2 years ago

find the coordinates of the point P on the parabola y=1-x^2 with domain 0≤x≤1 that minimize the area of the triangle enclosed by

coldgirl [10]

Let point P be with coordinates $(x_0,y_0).$ Find the equation of the tangent line.

1. If $y=1-x^2,$ then $y'=-2x.$

2. The equation of the tangent line at point P is

$y-y_0=-2x_0(x-x_0).$

Find x-intercept and y-intercept of this line:

when x=0, then $y=y_0+2x_0^2;$
when y=0, then $x=\dfrac{y_0}{2x_0}+x_0=\dfrac{y_0+2x_0^2}{2x_0}.$

The area of the triangle enclosed by the tangent line at P, the x-axis, and y-axis is

$A=\dfrac{1}{2}\cdot (2x_0^2+y_0)\cdot \left(\dfrac{y_0+2x_0^2}{2x_0}\right)=\dfrac{(y_0+2x_0^2)^2}{4x_0}.$

Since point P is on the parabola, then $y_0=1-x_0^2$ and

$A=\dfrac{(1-x_0^2+2x_0^2)^2}{4x_0}=\dfrac{(1+x_0^2)^2}{4x_0}.$

Find the derivative A':

$A'=\dfrac{2(1+x_0^2)\cdot 2x_0\cdot 4x_0-4(1+x_0^2)^2}{16x_0^2}=\dfrac{12x_0^4+8x_0^2-4}{16x_0^2}.$

Equate this derivative to 0, then

$12x_0^4+8x_0^2-4=0,\\ \\3x_0^4+2x_0^2-1=0,\\ \\D=2^2-4\cdot 3\cdot (-1)=16,\ \sqrt{D}=4,\\ \\x_0^2_{1,2}=\dfrac{-2\pm4}{6}=-1,\dfrac{1}{3},\\ \\x_0^2=\dfrac{1}{3}\Rightarrow x_0_{1,2}=\pm\dfrac{1}{\sqrt{3}}.$

And

$y_0=1-\left(\pm\dfrac{1}{\sqrt{3}}\right)^2=\dfrac{2}{3}.$

Answer: two points: $P_1\left(-\dfrac{1}{\sqrt{3}},\dfrac{2}{3}\right), P_2\left(\dfrac{1}{\sqrt{3}},\dfrac{2}{3}\right).$

6 0

2 years ago

The ratio of boys to girls in weekend volunteers is 5 to 6. There are 24 girls in the group. How many boys are there?

Zanzabum

there are 20 boys in the group.

5 0

2 years ago

Read 2 more answers