Ok so first we find the equation that equals one variable.
2y = -x + 9
3x - 6y = -15
We solve for y.
2y = -x + 9
y = -x/2 + 9/2
Then we plug in this y value into the other equation to keep only one variable so we can solve for it.
3x - 6y = -15
3(-x + 9/2) - 6y = -15
-3x + 27/2 - 6y = -15
-9y + 27/2 = -15
-9y = 3/2
-y = 3/18
y = -3/18
Then we plug in this numerical y-value into the first equation which we found out by solving an equation for y.
y = -x/2 + 9/2
-3/18 = -x/2 + 9/2
-84/18 = -x/2
-x = 9 1/3
x = -28/3
Your answer would be (-28/3, -3/18)
Hope this helps!
Answer:
65 miles
Step-by-step explanation:
There are two simultaneous equations
. Remeber that v=d/t, 1hour = 60 minutes.
1. 40 = (d+15)/(t+0.5)
2. 50 = d/t
solving: d= 25 miles and t=0.5 hours.
The distance traveled is:
D=d+d+15
D=65 miles
Answer:
The answers I have come are as follows.
-26
-14
-4
16
Okay so you take the number of weekdays to the number of weekends the ratio is 5:2 one month, which usually has 30 days which is 4 weeks tops so that is about 21 week days and and 9 weekends then times both by 12 you get 108 weekends and 252 weekdays i know that only equals 360 but this is a rough estimate so write that as a fraction 3/7 so there is a third that it will be on a weekday
12a + 6 + 3a = 15a + 2
15a = 15a - 4
0 = - 4
