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3 years ago

Which of the following is NOT AN EXAMPLE of personal identifying

Computers and Technology

2 answers:

Firlakuza [10]3 years ago

7 0

Answer:

I think

Your dog's name

Explanation:

I hope this helps you

alexgriva [62]3 years ago

6 0

Answer:

Your Social security number .

Explanation:

Personal information is the information of. a person.
It includes The name,Address,number etc of the person .
the PAN,Debit and credit card number is also included .

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3 years ago

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You have just read about a new security patch that has been made available for your Windows system, so you install the patch as

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3 years ago

When you ask the database more complex questions using comparison operators, you are conducting a _____. sort questionnaire quer

Mice21 [21]

The correct answer is known as a "query".

When you ask a lot of complex questions , which uses comparison operators, that is called a query. A query refers to the <span>exact request for </span>data retrieval<span> with the use of database and information systems. </span>

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3 years ago

a password to a certain database consists of digits that cannot be repeated. if the password is known to consist of at least 8 d

BaLLatris [955]

Answer:

$\frac{10!}{2}mins$

Explanation:

12 seconds to try one combination will be equivalent to $\frac{1}{12}\times 60 = \frac{1}{5} \ mins$

Password contain at least 8 digit i.e. password can contain 8, 9, 10 digit.

Password cannot contain more than 10 digit because it will give room for repetition which it is clearly stated that digit cannot be repeated.

Possible digit that can be used: 9,8,7,6,5,4,3,2,1,0.

Total number of passwords combination possible for each position in 8 digit.

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3. Total number of passwords combination possible in 8 digit is equivalent to $\frac{10!}{2}$ .

Total number of passwords combination possible for each position in 9 digit.

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3, 9th position = 2. Total number of passwords combination possible in 9 digit is equivalent to $\frac{10!}{1}$ .

Total number of passwords combination possible for each position in 10 digit.

1st position = 10, 2nd position = 9, 3rd position = 8, 4th position = 7, 5th position = 6, 6th position = 5, 7th position = 4, 8th position = 3, 9th position = 2, 10th position = 1. Total number of passwords combination possible in 10 digit is equivalent to 10!.

Adding them up and multiplying by $\frac{1}{5} \ mins$ to get the total number of time needed to guarantee access to database = $[\frac{10!}{2}\times\ \frac{10!}{1} \times 10!] \frac{1}{5}\ mins = \frac{10!}{2}$

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3 years ago