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slega [8]
3 years ago
14

How do I solve sinhx= -2 and sinhx=

" alt="\frac{7}{2}" align="absmiddle" class="latex-formula">
and get the answer in logs?
Mathematics
1 answer:
scoundrel [369]3 years ago
5 0

Answer:

Step-by-step explanation:

1)

sinh(x)=-2\\\\\dfrac{e^x-e^{-x}}{2} =-2\\\\e^{2x}-1=-4e^x\\\\(e^x)^2+4e^x-1=0\\\\\Delta=16+4=20\\\\e^x=\dfrac{-4-\sqrt{5} }{2} \ (exclude) \ or\ e^x=-2+\sqrt{5} \approx{0,236067977...}\\\\x=ln(-2+\sqrt{5} ) \approx{-1,443635475178...}\\\\

2)

sinh(x)=\dfrac{7}{2} \\\\\dfrac{e^x-e^{-x}}{2} =\dfrac{7}{2} \\\\e^{2x}-1=7e^x\\\\(e^x)^2-7e^x-1=0\\\\\Delta=49+4=53\\\\e^x=\dfrac{7-\sqrt{53} }{2} \ (exclude) \ or\ e^x=\dfrac{7+\sqrt{53}}{2} \approx{7,1400549...}\\\\x=ln(7+\sqrt{53} ) \approx{1,96572...}\\\\

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B is the right answer for you question
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The correct option is b.

Step-by-step explanation:

We have to find the product of \frac{2a-7}{a}  and  \frac{3a^2}{2a^2-11a+14}.

Multiply both terms.

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Cancel out the common factor a from numerator and denominator.

\frac{2a-7}{1}\times \frac{3a}{2a^2-7a-4a+14}

\frac{2a-7}{1}\times \frac{3a}{a(2a-7)-2(2a-7)}

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Cancel out the common factor (2a-7) from numerator and denominator.

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5 0
3 years ago
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You invested $500 in a savings account at the end of the 6th grade. The account pays 4% annual
pogonyaev

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Step-by-step explanation:

There are 12 grades in high school. So the number of years before graduation here is 6 years.

Now to know the amount of money, the equation to use is;

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Answer:

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