What the answer 2(+5)=3+1

Which statement tells a result of the big bang?

Nonamiya [84]

Answer:

Explanation:

Galaxies are moving closer

5 0

3 years ago

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A long, thin solenoid has 450 turns per meter and a radius of 1.17 cm. The current in the solenoid is increasing at a uniform ra

sergey [27]

Answer:

$\frac{di}{dt} = 7.31 \ A/s$

Explanation:

From the question we are told that

The number of turns is $N = 450 \ turns$

The radius is $r = 1.17 \ cm = 0.0117 \ m$

The position from the center consider is x = 3.45 cm = 0.0345 m

The induced emf is $e = 8.20 *10^{-6} \ V/m$

Generally according to Gauss law

$\int\limits { e } \, dl = \mu_o * N * \frac{di}{dt } * A$

=> $e * 2\pi x = \mu_o * N * \frac{d i }{dt } * A$

Where A is the cross-sectional area of the solenoid which is mathematically represented as

$A = \pi r ^2$

=> $e * 2\pi x = \mu_o * N * \frac{d i }{dt } * \pi r^2$

=> $\frac{di}{dt} = \frac{2e * x }{\mu_o * N * r^2}$ ggl;

Here $\mu_o$ is the permeability of free space with value

$\mu_o = 4\pi * 10^{-7} \ N/A^2$

=> $\frac{di}{dt} = \frac{2 * 8.20*10^{-6} * 0.0345 }{ 4\pi * 10^{-7} * 450 * (0.0117)^2}$

=> $\frac{di}{dt} = 7.31 \ A/s$

6 0

4 years ago

Which two objects have stored energy?

shepuryov [24]

a ball rolling on the ground

8 0

3 years ago

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The self inductance relates the magnetic flux linkage to the current through the coil. Calculate the self inductance L in units

Katen [24]

Answer:

Self inductance, $L=127\ \mu H$

Explanation:

It is given that,

Length of the coil, l = 5 cm = 0.05 m

Area of cross section of the coil, $A=3\ cm^2=0.0003\ m^2$

Number of turns in the coil, N = 130

The self inductance relates the magnetic flux linkage to the current through the coil and it is given by :

$L=\dfrac{\mu_oN^2A}{l}$

$L=\dfrac{4\pi \times 10^{-7}\times (130)^2\times 0.0003}{0.05}$

L = 0.000127 Henry

or

$L=127\ \mu H$

So, the self inductance of the coil is 127 microhenry. Hence, this is the required solution.

6 0

4 years ago

With time running out in a game, Rachel runs towards the basket at a speed of 2.5 meters per second and from half-court, launche

finlep [7]

Answer:

Rachel(2.5,0)

ball(6.5,4.7)

b.R=10.15m/s, 27.57deg

Explanation:

The reference angle of Rachel is 0 $0^{0} while the ball is at 36^{0}$

resolving rachel's speed to the horizontal, we have

Ux=2.5cos0

Ux=2.5m/s

resolving rachel's speed to the vertical we have,

Uy=2.5sin0

Uy=0

for the ball

resolving the speed to its horizontal component

Ux=8cos36

Ux=6.5m/s

Uy=8sin36

Uy=4.7m/s

Rachel(2.5,0)

ball(6.5,4.7)

To get the resultant of their speed

Add the horizontal speed of rachel to that of the ball to get the total horizontal speed

Add the vertical speed of rachel and the ball to get the total vertical speed component

TUx=2.5+6.5=9M/S

TUy=0+4.7=4.7m/s

R= $\sqrt{(TUx^2+TUy^2}$

R= $\sqrt{(9^2+4.7^2}$

R= $\sqrt{(103)}$

R=10.15m/s

the direction

tan $\alpha$ =TUy/TUx

tan $\alpha$ =4.7/9

$\alpha$ =tan^-1(0.522)

$\alpha$ =27.57deg

4 0

3 years ago