Excited
state is the name of the state when electrons absorb energy and move to
a higher energy level.
<span>In quantum mechanics, an </span>excited state<span> of
a system (such as an atom, molecule or nucleus) is any quantum</span>state<span> of
the system that has a higher energy than the ground </span>state<span> (that is, more energy than the
absolute minimum).</span>
The correct answer between all
the choices given is the second choice or letter B. I am hoping that this
answer has satisfied your query and it will be able to help you in your
endeavor, and if you would like, feel free to ask another question.
That's exactly the definition of <em><u>zero</u></em> acceleration ... no change in speed or direction.
Answer:
57.6
Explanation:
"Significant figures" refer to figures that have an actual contribution to a <em>number's value.</em>
They refer to all digits<u> except those with</u><em><u> </u></em><em><u>"leading zero,"</u></em> which means having a zero digit before a specific number. For example, in the number 0234, the significant figures are<em> 234. </em>
The rule for adding and subtracting significant figures is to <em>round off the answer to the least number of decimal places</em>. However, when it comes to multiplying and dividing significant figures, you have<em> round off the answer to the least number of significant digits.</em>
<u>Let's solve.</u>
21.4
+15
17.17
<u> 4.003</u>
57.573
Let's now round off to the<em> least number of decimal places</em>, which is the <em>tenths. </em>Since 0.5 is followed by a number greater than 5, we have to round it off to 6. Therefore, the answer is: 57.6
Answer:
#_foton2 = 2.96 10¹⁶ photon / s
Explanation:
We are going to solve this exercise in parts, first we will calculate how many photons are in the beam and then the amount that pass through the pinhole.
To find the energy of a photon, let's use the Planck relationship
E = h f
c = λ f
we substitute
E₀ = h c /λ
E₀ = 6.63 10⁻³⁴ 3 10⁸/337 10⁻⁹
E₀ = 5.90 10⁻¹⁹ J
Now we can use a direct ratio rule to find out the number of photons in the beam. If 1 photon has an energy E₀, how many photons are in an energy 5.00W
# _foton = 1 5/ E₀ = 1 5 / 5.90 10⁻¹⁹
#_foton = 8.5 10¹⁸ photons / s
This number of photons is uniformly distributed in the area of the circle with diameter 5.90mm = 5.90 10⁻³m
R= d/2= 2.95 10⁻³ m
r = d/2 = 0.55 10⁻³ m
let's find the beam area
A = π R²
A = π (2.95 10⁻³)²
A = 2.73 10⁻⁵ m²
the pinhole area
a = π r²
a = π (0.55 10⁻³)²
a = 9.50 10⁻⁷ m²
Let's use another direct ratio (rule of three) if there are 8.5 1018 photons / s in an area A how many photons pass through the area at
# _foton2 = 8.5 10¹⁸ a / A
# _fotn2 = 8.5 10¹⁸ 9.50 10⁻⁷ /2.73 10⁻⁵
#_foton2 = 2.96 10¹⁶ photon / s