Yes. Your answer is correct. I hope you do well on the quiz or whatever it is.
Answer:
2 m/s
Explanation:
Velocity is a vector quantity that is given by:
![v=\frac{d}{y}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bd%7D%7By%7D)
where
d is the displacement of the object (a vector indicating its change in position)
t is the time elapsed
Note that since velocity is a vector, it has both a magnitude and a direction (the same as the displacement).
For the toy train in this problem, we have:
d = 40 m (displacement)
t = 20 s (time elapsed)
So, its velocity is:
![v=\frac{40}{20}=2 m/s](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B40%7D%7B20%7D%3D2%20m%2Fs)
Answer:
(D) 23 Hz
Explanation:
We have given resistance ![R=11kohm=11\times 10^3ohm](https://tex.z-dn.net/?f=R%3D11kohm%3D11%5Ctimes%2010%5E3ohm)
Inductance L =24 H
Capacitance ![C=2\mu F=2\times 10^{-6}F](https://tex.z-dn.net/?f=C%3D2%5Cmu%20F%3D2%5Ctimes%2010%5E%7B-6%7DF)
We have to maximize the current so we need minimum impedance which is possible in case of resonance
In resonance condition ![X_L=X_C](https://tex.z-dn.net/?f=X_L%3DX_C)
![\omega L=\frac{1}{\omega C}](https://tex.z-dn.net/?f=%5Comega%20L%3D%5Cfrac%7B1%7D%7B%5Comega%20C%7D)
![\omega =\frac{1}{\sqrt{LC}}](https://tex.z-dn.net/?f=%5Comega%20%3D%5Cfrac%7B1%7D%7B%5Csqrt%7BLC%7D%7D)
![f =\frac{1}{2\pi \sqrt{LC}}](https://tex.z-dn.net/?f=f%20%3D%5Cfrac%7B1%7D%7B2%5Cpi%20%5Csqrt%7BLC%7D%7D)
![f =\frac{1}{2\times 3.14\sqrt{24\times 2\times 10^{-6}}}=22.98Hz=23Hz](https://tex.z-dn.net/?f=f%20%3D%5Cfrac%7B1%7D%7B2%5Ctimes%203.14%5Csqrt%7B24%5Ctimes%202%5Ctimes%2010%5E%7B-6%7D%7D%7D%3D22.98Hz%3D23Hz)
So option (D) is correct option
<span>A. How could energy become the matter present today? </span>
Answer:
-2.5 is the answer to your question