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4 years ago

11

In a two planet system, what happens to the period when velocity is maximized? a. It increases. c. It decreases. b. It remains c

onstant. d. No period can be calculated because the planet can escape the Sun's gravitational pull at high velocities.

2 answers:

Dmitry [639]4 years ago

7 0

D is the correct answer

bekas [8.4K]4 years ago

4 0

I think d but if its wrong im sorry

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A brass alloy is known to have a yield strength of 240 MPa (35,000 psi), a tensile strength of 310 MPa (45,000 psi), and an elas

Karo-lina-s [1.5K]

Answer:

Here Strain due to testing is greater than the strain due to yielding that is why computation of load is not possible.

Explanation:

Given that

Yield strength ,Sy= 240 MPa

Tensile strength = 310 MPa

Elastic modulus ,E= 110 GPa

L=380 mm

ΔL = 1.9 mm

Lets find strain:

Case 1 :

Strain due to elongation (testing)

ε = ΔL/L

ε = 1.9/380

ε = 0.005

Case 2 :

Strain due to yielding

$\varepsilon' =\dfrac{S_y}{E}$

$\varepsilon' =\dfrac{240}{110\times 1000}$

ε '=0.0021

Here Strain due to testing is greater than the strain due to yielding that is why computation of load is not possible.

For computation of load strain due to testing should be less than the strain due to yielding.

4 0

3 years ago

A 0.280-kg croquet ball makes an elastic head-on collision with a second ball initially at rest. The second ball moves off with

Jet001 [13]

Answer:

mass of second ball is 0.84 kg

Explanation:

mass of ball = 0.280 kg

to find out

mass of the second ball

solution

we know here elastic head on collision and

second ball moves = half the original speed

we consider here m1 mass of 1st ball and m2 mass of second ball

v1 = velocity of first ball before collision

v2 = velocity of second ball before collision

v3 = velocity of first ball after collision

v4 = velocity of second ball after collision

so here

we know 2nd ball was on rest so v2 = 0

after collision v4 = 1/2 ( v1)

and we know head on collision so

v3 = - v1/2

so from law of conservation of mass

m1v1 + m2v2 = m1v3 + m2v4

put here value

m1v1 + m2(0) = m1(-v1/2) + m2(v1/2)

solve and we get

m2 = 3m1

m2 = 3( 0.280) = 0.84

mass of second ball is 0.84 kg

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4 years ago

How do the full valance shells of the elements in the far right column of the periodic table affects how they react and take par

7nadin3 [17]

The full valence shell means that they do not react in chemical bonding.
The main purposes of chemical bonding is to obtain a stable structure.

Since the valence shell is stable,there is no need for chemical bonding since the whole atom is stable.

4 0

2 years ago

An airplane is flying at an elevation of 5150 ft, directly above a straight highway. two motorists are driving cars on the highw

docker41 [41]

Using trigonometric ratios we can get the distance;
For the first car; The distance from the point on the highway below the plane
tan = opp/adj
tan(36°) = 5150/x
0.727 = 5150/x
0.727x = 5150
x = 7088.37
For the second car we also use tangent; the distance from the point on the highway below the plane will be;
tan(56°) = 5150/y
1.483 = 5150/y
1.483y = 5150
y= 3473.72
The we can add the two distances to get how far apart the cars are;
7088.37 + 3473.72 = 10562.09 feet.
= 10562.09 ft

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3 years ago

An object with a 25 µC charge is 0.54 m away from a second charged object. They experience a force of 3250 N. What is the charge

nekit [7.7K]

25 uc charge is 0.54 m away

6 0

3 years ago