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4 years ago

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In a two planet system, what happens to the period when velocity is maximized? a. It increases. c. It decreases. b. It remains c

onstant. d. No period can be calculated because the planet can escape the Sun's gravitational pull at high velocities.

2 answers:

Dmitry [639]4 years ago

7 0

D is the correct answer

bekas [8.4K]4 years ago

4 0

I think d but if its wrong im sorry

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Step by step explanation

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3 years ago

A quantity of N2 occupies a volume of 1.4 L at 290 K and 1.0 atm. The gas expands to a volume of 3.3 L as the result of a change

lions [1.4K]

Answer:

$\rho = 0.50 g/L$

Explanation:

As we know that

PV = nRT

here we have

$P = 1.0 atm$

$P = 1.013 \times 10^5 Pa$

so we have

$V = 1.4 \times 10^{-3} m^3$

T = 290 K

now we have

$(1.013 \times 10^5)(1.4 \times 10^{-3}) = n(8.31)(290)$

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$m = (0.06)(28)$

$m = 1.65 g$

now density of gas when its volume is increased to 3.3 L

so we will have

$\rho = \frac{m}{V}$

$\rho = \frac{1.65 g}{3.3 L}$

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5 0

3 years ago

PLEASE HELP ASAP! i will really appreciate it

Setler79 [48]

What you’re doing is so easy pay attention more I think

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3 years ago

Two teams are playing tug-of-war. Team A, on the left, is pulling on the rope with an effort of 5000 N. If the rope is moving at

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Explanation:

If Team A is on the left, B is on the right

if the force is constant, it means that the effort applied is equal.

So Team B is pulling 5000N to the right.

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3 years ago

A 170 g air-track glider is attached to a spring. The glider is pushed in 11.2 cm against the spring, then released. A student w

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Answer:k = 10.83 N/m²

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Number of oscillations = 14, time taken = 11s

f = 14/11 = 1.27Hz.

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ω = 7.98 rad/s.

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Where ω = 7.98rad/s, m = 170g = 170/1000 = 0.17kg.

7.98 = √k/0.17

By squaring both sides

(7.98)² = k/ 0.17

k = (7.98)² × 0.17

k = 10.83 N/m²

7 0

4 years ago