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Flauer [41]
3 years ago
15

-1 whole 1/2 + (-1 whole 1/2)

Mathematics
1 answer:
OLEGan [10]3 years ago
4 0

Answer:

-3

Step-by-step explanation:

plz give me brainly

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Help me please thanks in advance
Xelga [282]

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From up to down ;

_________________________________

The first box :

f(n) = 3. ({2})^{n - 1}

The second box :

f(n) = 2. ({4})^{n - 1}

The third box :

f(n) = 2. ({6})^{n - 1}

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4 0
3 years ago
Maria, Hans, and Dan have a total of $95 in their wallets. Dan has 3 times what Hans has. Hans has $10 more than Maria. How much
mr Goodwill [35]
It looks like everyone's amount of money is based on Maria's amount of money.  Let's say Maria is M, Hans is H and Dan is D.  Maria has M amount of money.  If Hans has 10 more than Maria, he has M+10.  If Dan has 3 times what Hans has and Hans has (M+10), then Dan has 3(M+10) which is 3M+30.  Altogether they have 95 dollars.  So we will add up what they have and set it equal to 95.  M+10+M+30+3M=95.  That simplifies to 5M+40=95 and 5M=55.  Therefore, Maria has 11 dollars.  Hans has 10+11=21, and Dan has 3(21)=63.  11+21+63=95
5 0
4 years ago
Find A and B if sin2xcos3x = A sin 5x + B sin x
patriot [66]
Recall that

\sin(x+y)=\sin x\cos y+\cos x\sin y
\sin(x-y)=\sin x\cos y-\cos x\sin y

Adding these together, you have

\sin(x+y)+\sin(x-y)=2\sin x\cos y
\dfrac12\sin(x+y)+\dfrac12\sin(x-y)=\sin x\cos y

Replace x with 2x and y with 3x. You end up with

\dfrac12\sin(2x+3x)+\dfrac12\sin(2x-3x)=\sin2x\cos3x
\sin2x\cos3x=\dfrac12\sin5x+\dfrac12\sin(-x)=\dfrac12\sin5x-\dfrac12\sin x

and so A=\dfrac12 and B=-\dfrac12.
7 0
3 years ago
What’s 6 times 251 in expanded form? HELP!!
kramer

Answer:

1506

Step-by-step explanation:

1,506 = (1 x 1000) + (1 x 00) + (0 x 0) + (6 x 1)

8 0
4 years ago
Read 2 more answers
THIS QUESTION IS EASY, I JUST NEED EXPLANATION.
chubhunter [2.5K]

It would help to have the question. But I'll guess


\sqrt[4]{x^{\frac 3 5}}{\sqrt{x^2}} = ((x^{\frac 3 5})^{\frac 1 4}) }{ x} = x^{\frac 3{20}} x  = x \sqrt[20]{x^3}


2nd choice.


I forgot the explanation because I was so glad to have puzzled out the question.

The fourth root is the same as the 1/4 th power.   

If we know x is positive \sqrt{x^2}=|x|=x

\sqrt[4]{x^{\frac 3 5}}{\sqrt{x^2}}

= ((x^{\frac 3 5})^{\frac 1 4}) }{ x}

We multiply the powers: (a^b)^c=a^{bc}

= x^{\frac 3{20}} x

The one-twentieth power is the twentieth root.  We bring the additional factor of x to the front.

= x \sqrt[20]{x^3}

6 0
4 years ago
Read 2 more answers
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