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3 years ago

-1 whole 1/2 + (-1 whole 1/2)

Mathematics

1 answer:

OLEGan [10]3 years ago

4 0

Answer:

-3

Step-by-step explanation:

plz give me brainly

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Help me please thanks in advance

Xelga [282]

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From up to down ;

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The first box :

$f(n) = 3. ({2})^{n - 1}$

The second box :

$f(n) = 2. ({4})^{n - 1}$

The third box :

$f(n) = 2. ({6})^{n - 1}$

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4 0

3 years ago

Maria, Hans, and Dan have a total of $95 in their wallets. Dan has 3 times what Hans has. Hans has $10 more than Maria. How much

mr Goodwill [35]

It looks like everyone's amount of money is based on Maria's amount of money. Let's say Maria is M, Hans is H and Dan is D. Maria has M amount of money. If Hans has 10 more than Maria, he has M+10. If Dan has 3 times what Hans has and Hans has (M+10), then Dan has 3(M+10) which is 3M+30. Altogether they have 95 dollars. So we will add up what they have and set it equal to 95. M+10+M+30+3M=95. That simplifies to 5M+40=95 and 5M=55. Therefore, Maria has 11 dollars. Hans has 10+11=21, and Dan has 3(21)=63. 11+21+63=95

5 0

4 years ago

Find A and B if sin2xcos3x = A sin 5x + B sin x

patriot [66]

Recall that

$\sin(x+y)=\sin x\cos y+\cos x\sin y$
$\sin(x-y)=\sin x\cos y-\cos x\sin y$

Adding these together, you have

$\sin(x+y)+\sin(x-y)=2\sin x\cos y$
$\dfrac12\sin(x+y)+\dfrac12\sin(x-y)=\sin x\cos y$

Replace $x$ with $2x$ and $y$ with $3x$ . You end up with

$\dfrac12\sin(2x+3x)+\dfrac12\sin(2x-3x)=\sin2x\cos3x$
$\sin2x\cos3x=\dfrac12\sin5x+\dfrac12\sin(-x)=\dfrac12\sin5x-\dfrac12\sin x$

and so $A=\dfrac12$ and $B=-\dfrac12$ .

7 0

3 years ago

What’s 6 times 251 in expanded form? HELP!!

kramer

Answer:

1506

Step-by-step explanation:

1,506 = (1 x 1000) + (1 x 00) + (0 x 0) + (6 x 1)

8 0

4 years ago

Read 2 more answers

THIS QUESTION IS EASY, I JUST NEED EXPLANATION.

chubhunter [2.5K]

It would help to have the question. But I'll guess

$\sqrt[4]{x^{\frac 3 5}}{\sqrt{x^2}} = ((x^{\frac 3 5})^{\frac 1 4}) }{ x} = x^{\frac 3{20}} x = x \sqrt[20]{x^3}$

2nd choice.

I forgot the explanation because I was so glad to have puzzled out the question.

The fourth root is the same as the 1/4 th power.

If we know x is positive $\sqrt{x^2}=|x|=x$

$\sqrt[4]{x^{\frac 3 5}}{\sqrt{x^2}}$

$= ((x^{\frac 3 5})^{\frac 1 4}) }{ x}$

We multiply the powers: $(a^b)^c=a^{bc}$

$= x^{\frac 3{20}} x$

The one-twentieth power is the twentieth root. We bring the additional factor of x to the front.

$= x \sqrt[20]{x^3}$

6 0

4 years ago

Read 2 more answers