To determine the number of possible arrangements for 6 out of 8, we should use combinations. That is
ₐC₆ = 8!/(6!2!)
Answer: b. Combination
Given Equations :
✿ 2x + y = 20 ------------------ [1]
✿ 6x - 5y = 12 ----------------- [2]
Multiplying Equation [1] with 5, We get :
⇒ 5(2x + y) = 5(20)
⇒ 10x + 5y = 100 -------------- [3]
Adding Equations [2] and [3], We get :
⇒ (10x + 5y) + (6x - 5y) = 100 + 12
⇒ 16x = 112
⇒ x = 7
Substituting x = 7 in Equation [1], We get :
⇒ 2(7) + y = 20
⇒ 14 + y = 20
⇒ y = 20 - 14
⇒ y = 7
So, The Solution for the Given System of Equations is : (x , y) = (7 , 7)
Answer:
The asnwer is 19
Step-by-step explanation:
Answer:
Mr. Lim will have $2500
Step-by-step explanation:
Given:
The total amount of money which Mr. Lim, Mr. Tan and Mr. Chan is $8650;
Mr. Lim has $450 more than what Mr. Tan has;
Mr. Chan has double the amount of money than what Mr. Tan has.
Therefore, if we assume that the amount of money Mr. Tan has as x, then...
Total money = Mr. Tan + Mr. Lim + Mr. Chan
therefore,
8650 = x + (x + 450) + 2x
8650 = <u>x + 2x + x</u> + 450
8650 = 4x <u>+ 450</u>
8650 - 450 = 4x
8200 = <u>4</u>x
8200/4 = x
2050 = x
As we assumed earlier, x will be equal to the amount of money Mr. Tan has and the question is asking us how much money Mr. Lim has. To find this out, you have to add $450 to the amount of money Mr. Tan has which is $2050. This is because the question also gives us that Mr. Lim has $450 more that Mr. Tan.
I hope this helped you :)
So the possible numbers are multiples of 6 smaller than 24:
6
12
18
24 is not ok, since he won both kinds of trophies, so if he won 24 soccer trophies, he'd have no baseball trophies!
if he had 12 of one kind of trophies, he'd have 24-12=12 also 12 of the other trophies, and we know that he has more soccer trophies, so we reject this
so he has 6 and 18 trophies of one kind. Since he has more soccer trophies, this means that he has 18 soccer trophies and 6 baseball trophies!
