Use a Mohr circle to find the maximum shear stress relative to the axial stress.
Here we assume the axial stress is sigma, the transverse axial stress is zero.
So we have a Mohr circle with (0,0) and (0,sigma) as a diameter.
The centre of the circle is therefore (0,sigma/2), and the radius is sigma/2.
From the circle, we determine that the maximum stress is the maximum y-axis values, namely +/- sigma/2, at locations (sigma/2, sigma/2), and (sigma/2, -sigma/2).
Given that the maximum shear stress is 60 MPa, we have
sigma/2=60 MPa, or sigma=120 MPa.
(note: 1 MPa = 1N/mm^2)
Therefore
100 kN/(pi*d^2/4)=100,000 N/(pi*d^2/4)=120 MPa where d is in mm.
Solve for d
d=sqrt(100,000*4/(120*pi))
=32.5735 mm
Answer: -2
Step-by-step explanation:
Answer:
True
Step-by-step explanation:
Each time a spinner is spun, there is an equal chance that each result will occur, thus each of these spins are independent.
Answer:
B is 4 because there is no other one digit number that is a common multiple of 4
Step-by-step explanation:
