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Tatiana [17]
3 years ago
7

Erica sells magazine subscriptions and makes a flat rate of $5.35 for each subscription see cells if Erica man $42.80 on Monday

$64.20 on Tuesday and $74.90 on Wednesday how many subscriptions did she sell in three days
Mathematics
2 answers:
Kay [80]3 years ago
4 0
Erica would have sold 121 subscriptions in 3 days.
Tcecarenko [31]3 years ago
4 0

C—34. Subscriptions


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2 years ago
What is 3/4 times 6 to the power of 3
Olin [163]
64 1/8 or 64.125   thats my answer                                                                          
5 0
3 years ago
Read 2 more answers
Find the equation of a line passing through (-4,-3) and perpendicular to<br> 3 x + 2 y = 14.
Reil [10]

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the equation above

3x+2y=14\implies 2y=-3x+14\implies y=\cfrac{-3x+14}{2}\implies y = \cfrac{-3x}{2}+\cfrac{14}{2} \\\\\\ y=\stackrel{\stackrel{m}{\downarrow }}{-\cfrac{3}{2}}x+7\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

so therefore

\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{\cfrac{-3}{2}} ~\hfill \stackrel{reciprocal}{\cfrac{2}{-3}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{2}{-3}\implies \cfrac{2}{3}}}

so we're really looking for the equation of a line whose slope is 2/3 and passes through (-4 , -3)

(\stackrel{x_1}{-4}~,~\stackrel{y_1}{-3})\qquad \qquad \stackrel{slope}{m}\implies \cfrac{2}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-3)}=\stackrel{m}{\cfrac{2}{3}}(x-\stackrel{x_1}{(-4)}) \implies y+3=\cfrac{2}{3}(x+4) \\\\\\ y+3=\cfrac{2}{3}x+\cfrac{8}{3}\implies y=\cfrac{2}{3}x+\cfrac{8}{3}-3\implies y=\cfrac{2}{3}x-\cfrac{1}{3}

3 0
2 years ago
In a circle, a 90° sector has area 16π ft2. What is the radius of the circle?
Veronika [31]
Sector area  = 0.5 * r^2 * angle (in radians)

so:

16 pi = 0.5 * r^2 * (90*pi/180)

r^2 = 16 pi /(0.25 pi) = 64

r = 8


therefore it would be d
7 0
2 years ago
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