Answer:
Defenitely b, fossils, I don't think any of the others are right, But I could be wrong.
To calculate the frequency of the heterozygote genotype (Pq) for this gene we must use the Hardy-Weinberg equation ( p2 + 2pq + q2 = 1 ). This equation relies on the Hardy-Weinberg principle, a model in population genetics that states that the frequency of the alleles in a population is never changing, only the combinations (the genotypes) are changing.
If there are only two alleles (variations) of this gene in a population, then their frequencies should add up to 1 (100%). From this, we can calculate the frequency of the q allele.
p +q=1
0,3 +q=1
q= 1-0,3
q= 0,7
Now hat we have the frequency of the q allele we can use the HW equation to calculate the frequency of the heterozygotes.


0,09 + 2pq +0.49= 1
2pq +0,58= 1
2pq= 1-0.58
2pq=0,42
The freqency of the heterozygotes in this population is 0.42
Answer:
Overharvesting
Explanation:
Too much harvest and planting causes the soil to wear down and be less useful.
Answer:
a). Major products of glycolysis include pyruvate, ATP , and NADH
b) Glycolysis is the process by which glucose is converted to two molecules of pyruvate.
Explanation:
Glycolysis is a process in which a glucose molecule is broken down into two molecules of pyruvate. The process of glycolysis occurs without oxygen therefore it can occur in both aerobes and anaerobes.
The process of glycolysis occurs in the cytoplasm of the cell and the products of glycolysis are 2 molecules of pyruvate, 2ATP, and 2 NADH molecule. Then the pyruvate molecule gets into mitochondria which it's complete oxidation takes place. Therefore the right answer is a and b.