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schepotkina [342]
3 years ago
11

Given the ratio of 8 ounces to 1 cup, how many ounces are in 4 cups?

Mathematics
1 answer:
malfutka [58]3 years ago
6 0

Answer:

There are 32 ounces in 4 cups

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Evaluate the expression for s = -9.<br> 2s + 16 =
julia-pushkina [17]

Answer:

2s+16

2*(-9)+16

-18+16

-2

3 0
3 years ago
Solve for x.<br><br><br><br> 2x/3 + 1 = 3<br><br> x = 1 <br> x = 6<br> x = 3<br> x = 2
snow_tiger [21]

Answer:

your answer is x = 3

8 0
4 years ago
An experiment consist of rolling 3 fair dice (1 red die, a blue die, and a white die) and recording the number rolled on each di
Setler79 [48]
In 1, t<span>here are 6 outcomes for each die, so for three dice, the total combination is 6 x 6 x 6 = 216 outcomes. Hence, t</span><span>he probability of any individual outcome is 1/216 </span>

The outcomes that will add up to 6 are 
<span>1+1+4 </span>
<span>1+4+1 </span>
<span>4+1+1 </span>
<span>1+2+3 </span>
<span>1+3+2 </span>
<span>2+1+3 </span>
<span>2+3+1 </span>
<span>3+1+2 </span>
<span>3+2+1 </span>
<span>2+2+2 </span>

<span>Hence the probability is </span><span>10/216 </span>

In 3, the minimum sum of the three dice is 3. so we start with this 
<span>P(n = 3) </span>
<span>1+1+1 ; </span><span>1/216 </span>

<span>P(n = 4) </span>
<span>1+1+2 </span>
<span>1+2+1 </span>
<span>2+1+1 ; </span><span>3/216 </span>

<span>P(n = 5) </span>
<span>1+1+3 </span>
<span>1+3+1 </span>
<span>3+1+1 </span>
<span>1+2+2 </span>
<span>2+1+2 </span>
<span>2+2+1; </span><span>6/216 

The sum in 3 is 10/216 or 5/108</span>
3 0
4 years ago
Need help on these 2
Ostrovityanka [42]

Answer:5. the average is 2 million for football which is not much compared to basketball and football because the average is 8.2 million for basketball and 4.17 million for baseball

Step-by-step explanation:

5 0
3 years ago
*I WILL MARK YOU BRAINLIEST!!!!!*
AlekseyPX
<h2><em> </em><em>Answer:</em></h2>

<em>-</em><em>3</em>

<em>Explanation</em><em>:</em>

<em>Rate </em><em>of </em><em>change </em><em>in </em><em>the </em><em>interval</em>

<em>X=</em><em>0</em><em> </em><em>to </em><em>X=</em><em>3</em><em> </em><em>is </em><em>given </em><em>by,</em>

<em>r =  \frac{f(3) - f(0)}{3 - 0}  \\ here \\ f(3) = 1 \\ f(0) = 10 \\ r =  \frac{1 - 10}{3}  \\  \:  \:  \:  =  \frac{ - 9}{  3}  \\  \:  \:  \:  \:  =  - 3 \\ hope \: it \: helps.....</em>

4 0
4 years ago
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