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lina2011 [118]
3 years ago
7

The student government-collected data on club membership by grade level. Data on club membership are summarized in the table sho

wn below.
Grade Level Club Membership No Club Membership Total
9 125 250 375
10 165 155 320
11 201 101 302
12 206 69 275
Total 697 575 1272

a.no, bc P(Club Membership) not equal to P(12)
b. no, bc P(Club Membership/Grade 12) not equal to P( Club Membership)
c.yes because P(Grade 12)= P(Club Membership)
d.yes because P(Grade 12/PClub Membership) = P(Grade 12)
Mathematics
1 answer:
Musya8 [376]3 years ago
8 0

Answer:

d.yes because P(Grade 12/PClub Membership) = P(Grade 12)

Step-by-step explanation:

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Answer: 0.0278

Step-by-step explanation:

On a fair dice , there are six numbers (1,2,3,4,5,6) written on each face of dice.

Thus, when we thrown two dice , the sample space for the possibilities of outcomes will become :

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

i.e. Total number of outcomes = 36

For event A: { 3 appears on each of two dice.}

The favorable outcome = (3,3)

Now, the required probability : P(A)=\dfrac{\text{Number of favorable outcomes}}{\text{Total outcomes}}

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Hence, the required probability is 0.0278.

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Answer:

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