Answer:
The correct answer is : due to the hydrogen ions reacts and release high amount of energy with the strong acid.
Explanation:
Diluted acids are more corrosive then undiluted due to the presence of more H+ ions than the undiluted acids. The More the H+ ions are added the more corrosive the acid is.
When water is mixed with strong acid the hydrogen ions reacts with acid ions and a exothermic reaction takes place that release high amount of energy which boils violently, to avoid any accident it is advised to lab workers to wipe if any splash self before washing.
Thus, the correct answer is : due to the hydrogen ions reacts and release high amount of energy with the strong acid.
Given: The population density of frogs in a portion of a pond is 12 frogs per square meter. The size of the entire pond is 370 square meters.
To find: The total population size of the frogs in the pond.
Method: Using unitary method of proportions
Solution:
Let p be the density of the frogs present per square meter.
Let A denote the total area of the pond.
∴ p = 12 frogs/m² and A = 370 m²
The total number of frogs in the pond is given by,
Therefore, there are 4440 frogs in the pond.
Our diets are composed of protein, fat and carbohydrates. Digestive enzymes<span> break down protein, carbohydrates and fats into smaller and smaller components.</span>
Answer:
a) water will move from the cell into the beaker acroas the cell membrane
b) solutes will diffuse into the cell
Explanation:
a) Osmosis is the phenomenon that describes the movement of water from a region of low solute concentration (high water concentration) to a region of high solute concentration (low water concentration) across a semi-permeable membrane. In this case, since the inside of the cell contains a lesser concentration of solute (150mm), water containing dissolved solutes will move osmotically into the solution of the beaker, which has a higher concentration of solute (500mM) via the cell membrane (semi-permeable membrane).
b) Diffusion involves the movement of particles or molecules from a region where they are highly concentrated to a region where they are less concentrated. In this case, solutes/ions will diffuse from the beaker (outside the cell) containing 500mM of solute INTO THE CELL containing 150mM of solute.
