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3 years ago

The frog population at a lake doubles every week. The population can be modeled by

2 answers:

8 0

The answer is C. The rate the population increases. The 960 in the equation represents the population at a certain number of weeks which is x. The starting population describes the quantity 15. The number of weeks that have passed is described as the 6 weeks.

The equation would be described as: f(x) =15*(2^x) and f(x) =960

anygoal [31]3 years ago

8 0

The answer is C.The rate the population increases. The 960 in the equation represents the population at a certain number of weeks which is x. The starting population describes the quantity 15. The number of weeks that have passed is described as the 6 weeks.

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A particle is moving along a projectile path where the initial height is 96 feet with an initial speed of 16 feet per second. Wh

leonid [27]

Answer:

The maximum height of the particle is 100 ft

A is correct

Step-by-step explanation:

A particle is moving along a projectile path where the initial height is 96 feet with an initial speed of 16 feet per second.

The standard equation of parabolic projectile.

$h(t)=-16t^2+v_0t+h_0$

where,

$v_0=16\ ft/s$

$h_0=96\ ft$

$h(t)=-16t^2+16t+96$

So, we get the parabolic equation of path.

The maximum value at vertex.

$t=-\dfrac{b}{2a}$

$t=-\dfrac{16}{-32}=\dfrac{1}{2}$

Maximum at t=0.5

$h(0.5)=-16(0.5)^2+16(0.5)+96$

$h(0.5)=100$

Hence, The maximum height of the particle is 100 ft

4 0

3 years ago

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jennifer scored 75 on her quiz last week. this week she scored 90. what was the percent of increase on the quiz score?

Arlecino [84]

Answer:

The answer is a 20% increase

Hope this helps!

Mark me brainliest if I'm right :)

4 0

3 years ago

A certain animated movie earned $ 1 . 1 ? 1 0 9 $1.1?10 9 in revenues at the box office. The movie lasts 9 . 1 ? 1 0 1 9.1?10 1

Leokris [45]

Answer:

$ $1.21\times 10^{7}$ per minute.

Step-by-step explanation:

We have been given that a certain animated movie earned $ $1.1\times10^{9}$ in revenues at the box office. The movie lasts $9.1\times10^{1}$ minutes.

To find the revenue earned per minute of the movie we will will divide $1.1\times10^{9}$ by $9.1\times10^{1}$ .

$\text{The revenue earned per minute by the movie}=\frac{1.1*10^{9}}{9.1*10^{1}}$

Using quotient rule of exponents we will get,

$\text{The revenue earned per minute by the movie}=\frac{1.1}{9.1}*10^{(9-1)}$

$\text{The revenue earned per minute by the movie}=\frac{1.1}{9.1}*10^{8}$

$\text{The revenue earned per minute by the movie}=0.1208791208791209\times 10^{8}$

We can write 0.1208791208791209 as $1.208791208791209\times10^{-1}$ .

$\text{The revenue earned per minute by the movie}=1.208791208791209\times 10^{-1} \times 10^{8}$

Using product rule of exponents we will get,

$\text{The revenue earned per minute by the movie}=1.208791208791209\times 10^{-1+8}$

$\text{The revenue earned per minute by the movie}=1.208791208791209\times 10^{7}$

Upon rounding our answer to two decimal places we will get,

$\text{The revenue earned per minute by the movie}=1.21\times 10^{7}$

Therefore, the movie had earned a revenue of $ $1.21\times 10^{7}$ per minute.

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4 years ago

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Which number is closest to 51.4?

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Answer:

Step-by-step explanation:

Because its not exactly 40 and its .002 far away from beign 51.4

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Answer:

a rational number

Step-by-step explanation:

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