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2 years ago

If r = 9,6 = 5, and g = -6, what does (r+b-9) (b+g) equal?

Mathematics

1 answer:

devlian [24]2 years ago

6 0

Answer:

-5

Explanation:

First, expand.

r + b - 9 × b + g.

If r = 9, b = 5, and g = -6, this would be the answer:

9(r) + 5(b) - 9 = 5

5(b) + -6(g) = -1

5 × -1 = -5

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Answer:

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We need to find the area of triangle

Given E(5,1), F(0,4), D(0,8)

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Length of side DE = a = $=\sqrt{(5-0)^2+(1-8)^2}\\=\sqrt{(5)^2+(-7)^2}\\=\sqrt{25+49}\\=\sqrt{74}\\=8.60$

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Length of side EF = b = $=\sqrt{(0-5)^2+(4-1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\=5.8$

Length of side FD = c = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Length of side FD = c = $=\sqrt{(0-0)^2+(8-4)^2}\\=\sqrt{(0)^2+(4)^2}\\=\sqrt{0+16}\\=\sqrt{16}\\=4$

so, a= 8.60, b= 5.8 and c = 4

s = a+b+c/2

s= 8.6+5.8+4/2

s= 9.2

Area of triangle= $=\sqrt{s(s-a)(s-b)s-c)}\\=\sqrt{9.2(9.2-8.6)(9.2-5.8)(9.2-4)}\\=\sqrt{9.2(0.6)(3.4)(5.2)}\\=\sqrt{97.5936}\\=9.88$

So, area of triangle is 9.88 units^2

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