Since 8 students take both, that leaves only 4 students who take Algebra I alone.
Likewise since 8 students take both, that leaves 10 who only take Algebra 2
So out of the 60, twenty two are taking either Alg I Alg Ii or both.
That leaves 38 people who are not taking either.
b. 38
You can set this up using a 2 circle venn diagram. Just be sure to put the 8 who take both in first.
Answer:
QR ≈ 16.2 ft
Step-by-step explanation:
Using the tangent ratio in the right triangle.
tan62° =
=
=
( multiply both sides by 8.6 )
8.6 × tan62° = QR , then
QR ≈ 16.2 ft ( to the nearest tenth )
Answer:

Refer to the attachment for explication of steps. :)
Answer:
(2, 3 )
Step-by-step explanation:
Given the 2 equations
3x - 5y = - 9 → (1)
x + 2y = 8 → (2)
Multiplying (2) by - 3 and adding to (1) will eliminate the x- term, that is
- 3x - 6y = - 24 → (3)
Add (1) and (3) term by term to eliminate x
(3x - 3x) + (- 5y - 6y) = (- 9 - 24), that is
- 11y = - 33 ( divide both sides by - 11 )
y = 3
Substitute y = 3 into either of the 2 equations and solve for x
Substituting in (2)
x + 2(3) = 8
x + 6 = 8 ( subtract 6 from both sides )
x = 2
Solution is (2, 3 )
Answer:
3.) 0.894
Step-by-step explanation:
✔️First, find BD using Pythagorean Theorem:
BD² = BC² - DC²
BC = 17.89
DC = 16
Plug in the values
BD² = 17.89² - 16²
BD² = 64.0521
BD = √64.0521
BD = 8.0 (nearest tenth)
✔️Next, find AD using the right triangle altitude theorem:
BD = √(AD*DC)
Plug in the values into the equation
8 = √(AD*16)
Square both sides
8² = AD*16
64 = AD*16
Divide both sides by 16
4 = AD
AD = 4
✔️Find AB using Pythagorean Theorem:
AB = √(BD² + AD²)
AB = √(8² + 4²)
AB = √(64 + 16)
AB = √(80)
AB = 8.9 (nearest tenth)
✔️Find sin x using trigonometric ratio formula:
Reference angle = x
Opposite side = BD = 8
Hypotenuse = AB = 8.944
Thus:
(nearest thousandth)