
![\bf \stackrel{\textit{multiplying both sides by LCD of 3}}{3(y+5)=3\left[ \cfrac{5}{3}(x-3) \right]}\implies 3y+15=5(x-3) \\\\\\ 3y+15=5x-15\implies -5x+3y=-30\implies \stackrel{\textit{multiplying by -1}}{5x-3y=30}](https://tex.z-dn.net/?f=%5Cbf%20%5Cstackrel%7B%5Ctextit%7Bmultiplying%20both%20sides%20by%20LCD%20of%203%7D%7D%7B3%28y%2B5%29%3D3%5Cleft%5B%20%5Ccfrac%7B5%7D%7B3%7D%28x-3%29%20%5Cright%5D%7D%5Cimplies%203y%2B15%3D5%28x-3%29%0A%5C%5C%5C%5C%5C%5C%0A3y%2B15%3D5x-15%5Cimplies%20-5x%2B3y%3D-30%5Cimplies%20%5Cstackrel%7B%5Ctextit%7Bmultiplying%20by%20-1%7D%7D%7B5x-3y%3D30%7D)
bearing in mind the standard form uses all integers, and the x-variable cannot have a negative coefficient.
Answer:

Step-by-step explanation:
Question: 5 - 7(z+1) = 7(-9-3z)
We multiply the number in front of the bracket first, since that is multiplication.
--> 5 -7z -7 = -63 - 21z
--> -7z -2 = -63 - 21z
Now, we move all the z and all the numbers to each side.
--> -7z +21z = -63 +2
--> 14z = -61
--> z = -61/14
This cannot be simplified further, so z is -61/14.
Answer:
<u>36 tables are used to seat the students at the banquet: 12 rectangular and 24 round.</u>
Step-by-step explanation:
1. Let's review the information given to us to answer the question correctly:
Round tables = 8 seats
Rectangular tables = 12 seats
Ratio of round tables to rectangular tables = 2:1
Number of students = 336
2. How many tables are used to seat 336 students at the banquet, if no table has an empty seat?
x = Number of rectangular tables
2x = Number of round tables
Let's solve for x, using this equation:
12x + 8 (2x) = 336
12x + 16x = 336
28x = 336
x = 336/28
x = 12 ⇒ 2x = 24
12 + 24 = 36
<u>36 tables are used to seat the students at the banquet: 12 rectangular and 24 round.</u>
Answer:
7 friends
Step-by-step explanation:
Given the inequality expression
17(g+2)+45.99<200
We are to find the value of g that satisfies the inequality
Expand
17g+34 +45.99<200
17g+79.99<200
Subtract 79.99 from both sides
17g+79.99-79.99<200-79.99
17g<120.01
g<120.01/17
g<7.059
Hence the max number of friend that can attend is 7friends.