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bixtya [17]
2 years ago
14

A square and a rectangle have the same perimeter is the length of the side of the square is 4X minusone the score of the rectang

le is 2X + 2 and the width is 2X right and solve an equation to find X
Mathematics
1 answer:
Assoli18 [71]2 years ago
5 0

Square Perimeter = 4(4x-1)

Rectangle Perimeter = 2(2x+1) + 2(x+2)

Square Perimeter = Rectangle Perimeter

4(4x-1) = 2(2x+1) + 2(x+2)

16x - 4 = 4x + 2 + 2x + 4

16x - 4 = 6x + 6

-6x +4 -6x +4

10x = 10

x = 1

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If it takes 4 gallons of gas to drive 92 miles how many miles can be driven using 6 gallons
AVprozaik [17]

Answer:

138

Step-by-step explanation:

as 92÷4 = 23 and 23x6 = 148

4 0
2 years ago
Read 2 more answers
Sakura speaks 150 words per minute on average in Hungarian, and 190 words per minute on average in Polish. She once gave cooking
marusya05 [52]

Answer:3 minute

Step-by-step explanation:

Sakura speaks hungarian =150 words per minute

Sakura speaks polish =190 words per minute

and it is given she speaks 270 more words in polish than in hungarian

She speaks for a total of 5 minutes

let she speaks hungarian for t mins

therefore 150\times t+270=190\left ( 5-t\right )

t=2 mins

therefore sakura speaks hungarian for 2 mins and polish for 3 mins

6 0
3 years ago
1. Carter will install fencing all around the flat area of his
MariettaO [177]

Answer:

Amount of fencing required = 75 yards

Step-by-step explanation:

Distance between the two points (x_1,y_1) and (x_2,y_2) is given by the formula,

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Distance between A(3, 6) and B(3, -2) = \sqrt{(3-3)^2+(6+2)^2}

                                                               = 8 yards

Distance between B(3, -2) and C(-7, 4) = \sqrt{(3+7)^2+(-2-4)^2}

                                                                = \sqrt{136}

                                                                = 11.66 ≈ 12 yards

Distance between C(-7, 4) and D(-7, -2) = \sqrt{(-7+7)^2+(4+2)^2}

                                                                 = 6 yards

Distance between D(-7, -2) and E(-3, -2) = \sqrt{(-7+3)^2+(-2+2)^2}

                                                                   = 4 yards

Distance between E(-3, -2) and F(-3, -8) = \sqrt{(-3+3)^2+(-2+8)^2}

                                                                = 6 yards

Distance between F(-3, -8) and G(3, -8) = \sqrt{(-3-3)^2+(-8+8)^2}

                                                                 = 6 yards

Distance between G(3, -8) and H(10, -12) = \sqrt{(3-10)^2+(-8+12)^2}

                                                                   = \sqrt{49+16}

                                                                   = \sqrt{65}

                                                                   = 8.06 ≈ 8 yards

Distance between H(10, -12) and J(10, 6) = \sqrt{(10-10)^2+(-12-6)^2}

                                                                   = 18 yards

Distance between A(3, 6) and J(10, 6) = \sqrt{(10-3)^2+(6-6)^2}

                                                               = 7 yards

Since length of fence required = perimeter of the flat area

Perimeter of the given area = 8 + 12 + 6 + 4 + 6 + 6 + 8 + 18 + 7

                                              = 75 yards

Therefore, amount of fencing required = 75 yards

8 0
3 years ago
You deposit $1500 in an account that pays 7% annual interest. Find the balance after 2 years when the interest is compounded dai
just olya [345]

A = $ 1,721.28

A = P + I where

P (principal) = $ 1,500.00

I (interest) = $ 221.28

3 0
3 years ago
Question 4. In the graph, lines f and g intersect at P(6,6). What is the area, in square units, of the shaded region? * E. 15 F.
erastova [34]

Answer:

E

Step-by-step explanation:

i guess the dotted lines outline a square

so get the area of the square which is 6×6=36

then don't focus on the shaded part but unshaded you'll see two right angled triangles

a = 1 \div2b \times h

you will get a total for both as 21

then get the area of the square 36-21=15

so the area becomes 15

3 0
2 years ago
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