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Paladinen [302]
3 years ago
14

Please help me im really confused and i need an answer and how to do it!

Mathematics
1 answer:
Nutka1998 [239]3 years ago
8 0

By solving the given equation of inequality "4x+5 \geq 21", we get "x \geq 4". A complete solution is below.

The given inequality equation is:

  • 4x+5 \geq 21

By subtracting "5" from both sides of the above equation, we get

→ 4x+5 -5 \geq 21-5

→             4x\geq 16

By applying cross-multiplication, we get

→               x \geq \frac{16}{4}

→               x \geq 4

Thus the answer above is the right one.

Learn more about inequality equation here:

brainly.com/question/12094806

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A large cylindrical cooler is 2 (1 )/2 feet high and has a diameter of 1 1/2 feet. It is filled
Mrac [35]
\bf \textit{volume of a cylinder}\\\\
V=\pi r^2 h\qquad 
\begin{cases}
r=radius=\frac{diameter}{2}\\
h=height\\
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diameter=1\frac{1}{2}\\\\
r=\cfrac{1\frac{1}{2}}{2}\\\\
h=2\frac{1}{2}
\end{cases}

so.. get the full volume of the cooler, by plugging in the given values

now, the cooler is only filled 3/4, how much is 3/4 of that? well, let's say you got a value V, 3/4 of that is , well \bf \cfrac{3}{4}\cdot  V
6 0
4 years ago
at 2 p.m.,the level of the water in the pool was 10 feet.at 6 p.m., the level of water was 2 feet.find the rate of change of the
kipiarov [429]
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4 0
4 years ago
Which is bigger 4/6 or .77
jok3333 [9.3K]
First, let's convert 0.77 to a fraction. 

\frac{0.77}{1}

Multiply by 100

\frac{77}{100}

Now make the denominators the same, to make it easier to find which fraction is greater. We can do this by finding the LCM of the denominators, then however many times the denominator goes into that number, we multiply the numerator by the same amount.

For example, the LCM of 100 and 6, is 300. 6 goes into 300 50 times, so the numerator for 4/6 is 200 (4 x 50 = 200). :)

\frac{200}{300} \ \textless \  \frac{231}{300}

The answer is 0.77 is greater than 4/6. :)

Hopefully this helps! If you have any more questions or don't understand, feel free to DM me, and I'll get back to you ASAP! :)
5 0
4 years ago
Read 2 more answers
How do you graph x+2÷(x^2-3x-10) without a calculator?
ahrayia [7]
First step is to simplify the equation into a form that we are familiar with graphing, in this case the simplest way i believe is to factorise the denominator. There are many methods of factorising quadratics but in this case my preferred method would be as follows:

x^2-3x-10, because it is a quadratic equation we know it can be factorised into the form (x+a)(x+b), we know that -10 is the product of a and b, therefore a and b can only be +/-1 and -/+10, or +/-5 and -/+2, the next step is to see which of these factors sum to equal -3, in this case it will be +2 and -5, therefore x^2-3x-10 can be factorised into (x+2)(x-5).

We have now simplified the function into f(x)= (x+2)/(x+2)(x-5), we can still simplify the function further though:

(x+2)/(x+2)(x-5), the numerator and denominator have a common factor therefore we can divide the numerator and the denominator by that factor, ((x+2)/(x+2))/((x+2)(x-5)/(x+2))= 1/(x-5) 

The function is now in it's simplest form, so we will now graph it. As a side note you can't perfectly "graph" any function by hand so instead we will sketch the function, to sketch a function you need to know the general shape of the function  and any x/y intercepts or asymptotes.        

Functions of the form a/(bx+c) are reciprocal functions, you need to be able to remember what reciprocal function looks like to be a able to sketch them by hand, they look something like this https://www.desmos.com/calculator/df2wiewhsz. To work out the x-intercept we will assign f(x) as 0, 0=1/(x-5), multiply both sides by (x-5), (x-5)0=1, 0=1, 0 doesn't equal 1 therefore there is no x-intercept but instead there is an asymptote at y=0. To work out the y-intercept we will assign x as 0, f(x)=1/(x-5), f(x)=1/-5, therefore the only y-intercept is at coordinates (0.-0.2). All reciprocal functions have 2 asymptotes, we have already found one of them, by making f(x)=0, to find the other asymptote we will make 1/(x-5)=∞, 1/0=∞, therefore x-5 has to equal 0, therefore the second asymptote will be x=5.

after putting all of this together the graph should look something like this https://www.desmos.com/calculator/bibeeu7xtv




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3 years ago
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trapecia [35]
Quadrant 4 .
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4 years ago
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